Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.
Answer:
Most substituted alkene is produced as a major product
Explanation:
- Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
- Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
- Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
- Reaction mechanism has been shown below.
Answer:
Each orbit has a specific energy level.
Would you mind marking it the brainliest:).
Answer:
A. 2 bonds
Explanation:
If you see a charch of ci20 it would easily show the answer.