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Phoenix [80]
3 years ago
10

Yogurt has an approximate pH of 5 and vinegar has an approximate pH of 3. How many times more acidic is vinegar compared to yogu

rt in terms of concentration?
Chemistry
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

The vinegar is highly acidic by 100 times than yogurt.

Explanation:

∵ pH = -log[H⁺]

  • The concentration of H⁺ in yogurt:

∵ pH = -log[H⁺]

∴ 5 =  -log[H⁺]

∴  [H⁺] = 1.0 x 10⁻⁵ M.

  • The concentration of H⁺ in vinegar:

∵ pH = -log[H⁺]

∴ 3 =  -log[H⁺]

∴  [H⁺] = 1.0 x 10⁻³ M.

the ratio of H⁺ in vinegar to that in yogurt = 1.0 x 10⁻³ M / 1.0 x 10⁻⁵ M = 100.0.

<em>∴ The vinegar is highly acidic by 100 times than yogurt.</em>

<em></em>

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3 years ago
Discuss whether two products are required for a chemical reaction. (NEED HELP ASAP)
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Answer:

Yes.

Explanation:

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Why is this mars landing a new era for space exploration
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3 0
3 years ago
You use 50.00 mL of a 12.0 M solution of HCl solution to make a 500.00 mL solution. What is the concentration of the new solutio
Alexandra [31]

Answer:

1.2 M

Explanation:

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6 0
3 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
3 years ago
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