To lift a load of 100 kg a distance of 1 m an effort of 25 kg must be applied over an inclined plane of length 4 m. What must be
2 answers:
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Here is the missing information.
An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .
Answer:
0.793 rad
Explanation:
From the given question:
The angular velocity of the wheel is expressed by the equation:
The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)
SO;
dθ = at dt - (b sin ct) dt
Taking the integral of the above equation; we have:
where;
a = 0.500 rad/s2 ,
b = 0.250 rad/s and
c = 2.00 rad/s
Hence, the angular displacement after two seconds = 0.793 rad
Answer:
Explanation:
Given data:
Mass of the paper clip,
Kinetic energy,
Let the velocity of the paper clip when it is thrown be <em>v</em>.
Thus,
(rounding to nearest tenth)