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MrRissso [65]
3 years ago
15

A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy

Physics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

v = 4.2 \ m/s

Explanation:

Given data:

Mass of the paper clip, m = 1.5 \ g = 0.0015 \ kg

Kinetic energy, K = 0.013 \ \rm J

Let the velocity of the paper clip when it is thrown be <em>v</em>.

Thus,

K = \frac{1}{2}mv^{2}

0.013 = 0.5 \times 0.0015 \times v^{2}

\Rightarrow \ v = 4.16 \ m/s

v = 4.2 \ m/s.  (rounding to nearest tenth)

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3 years ago
Which substance is uniquely a product of incomplete combustion of a fossil fuel?
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I can think of two of them:

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3 0
4 years ago
Two rows of fluorescent lamps are installed in an office on the same branch circuit, with each row drawing 12.5 amperes. The sou
klio [65]

Answer:

V_{load} = 264.5 Volts

Explanation:

As we know that the resistance of the wire is given as

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now we know that both the bulbs are getting 12.5 A current in their branches

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i = 12.5 + 12.5

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5 0
4 years ago
Two loudspeakers, d1 = 2.00 m, are in phase. Assume the amplitudes of the sound from the speakers are approximately the same at
Katarina [22]

Answer:

Lowest frequency that gives the minimum signal is 343 Hz

lowet frequency for maximum signal 686 Hz

Explanation:

D_1 = 2.00 m

D _2  =3.75 m

Δx = \sqrt {D_1^2 +D_2^2} - D_2

     =\sqrt {2.00^2 +3.75^2} - 3.75

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for minimum distructive interference,  the path difference is

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where c is speed of sound in air 343 m/s

f = \frac{343}{1} = 343 Hz

b) lowet frequency for maximum signal

for minimum CONSTRUCTIVE interference,  the path difference is

Δx = n\lambda  

for minimum n = 1

\lambda = Delta x

             = 0.5 m

lowest frequency f =\frac[c}{\lambda}

f  = \frac{343}{0.5} = 686 Hz

6 0
3 years ago
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A closed space zone is one that is obstrutced in some way.

Hope this helps :)
5 0
3 years ago
Read 2 more answers
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