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mamaluj [8]
4 years ago
15

3. Electrons move about the nucleus of an atom in regions called _____.

Physics
2 answers:
zmey [24]4 years ago
6 0
A. electron cloud
 
the others being bcd are wrong because b is the center of a atom where the protons and neutrons are c because air does notexist at that scale and d is just the different types of a atom 
irakobra [83]4 years ago
5 0
<span>Electrons move about the nucleus of an atom in regions called Electron clouds. 
This term is used to describe where electrons are when when they go around the nuclear of an atom.</span>
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Why is alpha rays not suitable to scan baggage at the airport?​
Inga [223]

Answer:

Alpha particles are not used to check baggage in airport as these rays are not penetrated far through matter.

<u>Explanation: </u>

Alpha particles are produced by the <em>decay of a radioactive nucleus.</em> These alpha rays are <em>ceased by paper</em>. The <em>nucleus</em> of the helium atom is made up of <em>two protons and two neutrons</em> is the particle <em>ejected by alpha particle</em>.

As helium is <em>harmless and as an inert gas</em>, so these particles are not dangerous in themselves. The airport baggage security uses only X-ray scanners to inspect. These rays identify the <em>hidden items inside the baggage. </em>

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3 years ago
On a riding lawn mower how long does it take to cut 5 acres
defon
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3 years ago
Calculate the mass of the earth if the radius of the earth is 6.38 × 10^6​
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3 years ago
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

T = 2 \pi \sqrt{\frac{m}{k} } \\

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k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

Hence the force constant of the spring is 17.71N/m

4 0
3 years ago
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