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lord [1]
3 years ago
10

Once the genes are copied, where do they go?

Physics
1 answer:
Anna [14]3 years ago
5 0

By copying their genomes, they retain the tool kit and at the same time generate a garage full of spare parts. Gene duplication can provide the raw material for expression changes to occur, and polyploidy itself can trigger epigenetic changes

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Vector has a magnitude of 6.0 m and points 30° north of east. Vector has a magnitude of 4.0 m and points 30° east of north. The
Brut [27]

Answer:

The resultant vector is \vec R = \vec A + \vec B = 7.196\,i + 6.464\,j.

Explanation:

First, each vector is determined in terms of absolute coordinates:

6-meter vector with direction: 30º north of east.

\vec A = (6\,m)\cdot (\cos30^{\circ} \,i + \sin 30^{\circ}\,j)

\vec A = 5.196\,i + 3\,j

4-meter vector with direction: 30º east of north.

\vec B = (4\,m)\cdot (\cos 60^{\circ}\,i + \sin 60^{\circ}\,j)

\vec B = 2\,i + 3.464\,j

The resultant vector is obtaining by sum of components:

\vec R = \vec A + \vec B = 7.196\,i + 6.464\,j

The resultant vector is \vec R = \vec A + \vec B = 7.196\,i + 6.464\,j.

5 0
4 years ago
How much tension does it take to snap someone's neck?
Nat2105 [25]
To break<span> the </span>neck<span> of a human, ~ 1,250 foot-pounds of torque is required. And this is without the person's resistance.</span>
3 0
3 years ago
Read 2 more answers
A refrigerator receives 240 V of electricity. If it uses 32 A of current, what is the resistance of the refrigerator?
Leokris [45]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Ohms Law,

According to the Ohms law,

V = I*R, where, V = Voltage, I = Current, R = resistance,

so here given as, V = 240 V, I = 32 A,

so we get as, R = 240/32

R = 7.5 ohms,

===> The resistant R is ==> 7.5 ohms.

7 0
3 years ago
An object has 100 J of kinetic energy and a mass of 2 g. How fast was it traveling?
iragen [17]

K.E = 1/2 mv²

100   = 1/2 (2 )(v)²

100  = both  2 cancel (v)²

Taking Square root on b/s

√100 = √v²

10  = v

7 0
4 years ago
A 2.1 kg block is dropped from rest from a height of 5.5 m above the top of the spring. When the block is momentarily at rest, t
ella [17]

Answer:

The speed of the block is 8.2 m/s

Explanation:

Given;

mass of block, m = 2.1 kg

height above the top of the spring, h = 5.5 m

First, we determine the spring constant based on the principle of conservation of potential energy

¹/₂Kx² = mg(h +x)

¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)

0.03125K = 118.335

K = 118.335 / 0.03125

K = 3786.72 N/m

Total energy stored in the block at rest is only potential energy given as:

E = U = mgh

U = 2.1 x 9.8 x 5.5 = 113.19 J

Work done in compressing the spring to 15.0 cm:

W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J

This is equal to elastic potential energy stored in the spring,

Then, kinetic energy of the spring is given as:

K.E = E - W

K.E = 113.19 J - 42.6 J

K.E = 70.59 J

To determine the speed of the block due to this energy:

KE =  ¹/₂mv²

70.59 =  ¹/₂ x 2.1 x v²

70.59 = 1.05v²

v² = 70.59 / 1.05

v² = 67.229

v = √67.229

v = 8.2 m/s

8 0
3 years ago
Read 2 more answers
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