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WARRIOR [948]
3 years ago
6

Prove p=f/a science chapter pressure​

Physics
1 answer:
Shalnov [3]3 years ago
6 0

Explanation:

Let 'F' be force acting perpendicularly, 'A' be the area and 'P' be the pressure exerted.

Then,

Pressure is directly proportional to the the force acting perpendicularly i.e.

P ∝ F ............. (i)

Pressure is inversely proportional to the area on which force acts i.e.

P ∝ 1/A ........... (ii)

Combining equations (i) and (ii),

P ∝ F/A

or, P = K × F/A [where K is a constant]

If F is 1N, A is 1m² and P is 1 N/m², then K is 1.

So, P = F/A proved...

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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
nexus9112 [7]

(a) The man comes to a halt in 1.99 ms = 1.99 × 10⁻³ s, so his average acceleration slowing him from 6.33 m/s to a rest is

<em>a</em> = (6.33 m/s - 0) / (1.99 × 10⁻³ s) ≈ 3180 m/s²

so that the average net force on the man during the landing is

<em>F</em> = (70.8 kg) <em>a</em> ≈ 225,000 N

i.e. with magnitude 225,000 N.

(b) With knees bent, the man has an average acceleration of

<em>a</em> = (6.33 m/s - 0) / (0.147 s) ≈ 43.1 m/s²

and hence an average net force of

<em>F</em> = (70.8 kg) <em>a</em> ≈ 3050 N

(c) The net force on the man is

∑ <em>F</em> = <em>n</em> - <em>w</em> = <em>m a</em>

where

<em>n</em> = magnitude of the normal force, i.e. the force of the ground pushing up on the man

<em>w</em> = the man's weight, <em>m g</em> ≈ 694 N

<em>m</em> = the man's mass, 70.8 kg

<em>g</em> = mag. of the acceleration due to gravity, 9.80 m/s²

<em>a</em> = the man's acceleration

Using the acceleration in part (b), we have

<em>n</em> = <em>m g</em> + <em>m a</em> = <em>m</em> (<em>g</em> + <em>a</em>)

<em>n</em> = (70.8 kg) (9.80 m/s² + 43.1 m/s²) ≈ 3740 N

4 0
3 years ago
4. A train starts its journey and accelerates at 5 ms 2. How long does it take for it to reach a velocity of 100 ms??
Agata [3.3K]

Answer:

20 seconds

Explanation:

6 0
3 years ago
Read 2 more answers
PHYSICS PLEASE HELP EASY!!<br> I put C and it was incorrect; I'm so confused :((
devlian [24]

Answer:

the answer is A i took this class and it was hard but once you know it you will be a master

Explanation:

8 0
3 years ago
An object is traveling at 15 m/s and then after 5 seconds ends up traveling at 10 m/s. Calculate the speeds acceleration rate. W
SSSSS [86.1K]

Answer:

1) a = -1 m/s²

2) v = 12 m/s

Explanation:

Given,

The initial velocity of the object, u = 15 m/s

The final velocity of the object, v = 10 m/s

The time taken by the object to travel is, t = 5 s

Using the first equation of motion

                               <em>v = u + at</em>

                               a = (v - u) / t

Substituting the values

                                a = (10 - 15) / 5

                                    = -1 m/s²

The negative sign indicates the body is decelerating

The acceleration of the object is, a = -1 m/s²

The speed of the object after 2 seconds

From the above equations of motion

                                  v = 15 + (-1) 2

                                     = 12 m/s

Hence, the speed of the object after 2 seconds is, v = 12 m/s

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4 years ago
on earth a block is placed on a frictionless table. When a 50 North horizontal force is applied to the block, it accelerates at
melamori03 [73]

As per Newton's II law we know that

F = ma

here

F = applied unbalanced force

m = mass of object

a = acceleration of object

now it is given that force F = 50 N North applied on block on earth due to which block will accelerate by 4 m/s^2

so here from above equation

50 = m* 4

m = \frac{50}{4} = 12.5 kg

Now we took another situation where block is placed on surface of moon and again force F = 25 N is applied on the block

So we will again use Newton's II law

F = ma

25 = 12.5 * a

a = \frac{25}{12.5}

a = 2 m/s^2

so block will accelerate on moon by acceleration 2 m/s^2

5 0
3 years ago
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