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andriy [413]
3 years ago
8

Please helpppp: A caterpillar tries to climb straight up a wall two meters high, but for every 2 cm up it climbs, it slides down

1 cm.
Eventually, it reaches the top. When it reaches the top, it does not pull itself over so it will slide down 1 cm.

In the first box, select the total displacement. In the second box, indicate the direction.

cm
Physics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

The caterpillar is climbing a wall of 2 meters.

the caterpillar climbs 2 cm, and then falls 1 cm, so for each "climb", the caterpillar actually moves 1cm, while the actual distance moved is 3 cm, the displacement is 1cm.

Remember, displacement is equal to the difference between the initial position and the last position.

Now, when the caterpillar reaches the top, it slides down one centimeter, so the final position of the caterpillar is:

2 meters - 1 centimeter, and 1 m = 100 cm

200 centimeters - 1 centimeter = 199 centimeters.

Knowing that the caterpillar started at the ground, at 0 centimeters, then we can find that the difference between the final position and the initial position is:

D = 199cm - 0cm = 199cm

The displacement is 199cm.

The direction is upwards, if we define the y-axis as the vertical axis, the the direction is in the positive y-axis.

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ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

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Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

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On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

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120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

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