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3 years ago

Describe how the three major types of deserts differ in their climate and vegetation. How do plants and animals survive?

Biology

1 answer:

egoroff_w [7]3 years ago

7 0

Answer:

1. Tropical deserts: Hot and dry most of the year; They have a few plants and a hard, windblown surface strewn with rocks and some sand.

2. Temperate deserts: Hot in the summer and cold in the winter; There is more precipitation than tropical deserts; The sparse vegetation primarily consists of widely dispersed, drought-resistant shrubs and cacti or other succulents adapted to the lack of water and temperature variations.

3. Cold deserts: Winters are cold, summers are warm or hot, and precipitation is low; Desert plants and animals have adaptations that help them to stay cool and to get enough water to survive.

Plants and animals survive because They have adaptations that help them to stay cool and to get enough water to survive

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What is the sample variance of the following data, which describe the height growth of 10 foxtal pine trees grown in a common ga

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Answer:

Although the data in the question is not clearly stated, the correct date is stated in the image attached to this answer and it is also stated below

What is the sample variance of the following data, which describe the height growth of 10 foxtail pine trees grown in a common garden ( give your answer to one decimal place)?

Tree Height(cm)

1 25.6987

2 19.6587

3 11.4780

4 9.11130

5 16.8747

6 14.7771

7 33.0001

8 24.0000

9 19.4441

10 14.1010

answer 51.9

Explanation:

what is a sample variance?

A sample variance (denoted as $S^{2}$ ) is used to calculate how far a set of numbers are from the mean value of the set. Mathematically, it is defined as the average of the squared deviations from its mean value.

Let the individual value of the trees be represented as x₁ to x₁₀

Let the total number of Foxtail pine trees be N

To calculate the standard deviation, we will first calculate the mean or average of the height of the trees

1. Mean (μ) = $\frac{x_{1}+x_{2}+x_{3}+x_{4}+x_{5}+x_{6}+x_{7}+x_{8}+x_{9}+x_{10} }{N}$

= $\frac{25.6987+19.6587+11.4780+9.11130+16.8747+14.7771+33.0001+24.0000+19.4441+14.1010}{10}$ = $\frac{188.1437}{10} = 18.8144$

2. we need to calculate the sum of the squares of the individual deviations.

∑[x-μ]²= $(25.6987-18.8144)^{2}+(19.6587-18.8144)^{2}+(11.4780-18.8144)^{2}+(9.11130-18.8144)^{2}+(16.8747-18.8144)^{2}+(14.7771-18.8144)^{2}+(33.0001-18.8144)^{2}+(24.0000-18.8144)^{2}+(19.4441-18.8144)^{2}+(14.1010-18.8144)^{2}=466.8786$

3. Now the variance is ; (∑[x-μ]²) ÷ (N-1) and since N=10, then N-1 = 10-1 = 9

= $\frac{466.8786}{9} = 51.8754.$

we were asked the give our answer to one decimal place

∴ Variance( $S^{2}$ )= 51.9

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