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2 years ago

5

What type of weathering is best expressed in this weathered limestone?

1 answer:

DENIUS [597]2 years ago

6 0

It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, here is the answer. The type of weathering that is best expressed in this weathered limestone is DISSOLUTION. Hope this answers your question. Have a great day!

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A very hard rubber ball (m = 0.5 kg) is falling vertically at 4 m/s just before it bounces on the floor. The ball rebounds back

saw5 [17]

Answer:

The force exerted by the floor is 80 N.

Explanation:

Given that,

Mass of ball = 0.5 kg

Velocity= 4 m/s

Time t = 0.05 s

When the ball rebounds then the kinetic energy is

$K.E =\dfrac{1}{2}mv^2$

Where, m = mass of ball

v = velocity of ball

Put the value into the formula

$K.E=\dfrac{1}{2}\times0.5\times(4)^2$

$K.E = 4\ J$

The average force exerted by the floor on the ball = change in kinetic energy over collision time

$F = \dfrac{4}{0.05}$

$F=80\ N$

Hence, The force exerted by the floor is 80 N.

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2 years ago

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3 years ago

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2 years ago

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Mazyrski [523]

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3 years ago

Hi, so i have to find T1, can some1 help?

iragen [17]

30.1 N

Explanation:

Given:

$W_1 = 16\:\text{N}$

$W_2 = 8\:\text{N}$

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

$x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)$

$y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)$

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

$x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)$

$y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)$

Substitute (2) into (3) and we get

$T_1\sin 53 - W_1 = W_2$

Solving for $T_1$ ,

$T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}$

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2 years ago