The force between two parallel wires carrying currents in the same direction is attractive. It is repulsive if the currents are in opposite directions.
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<span>(6.0x10^-22, -1.40x10^-21, 0) kg*m/s
Momentum is a conserved quantity. The total momentum of the system before and after the interactions will not change. So, let's look at the momentum before the interaction.
(3.2x10^-21, 0, 0) kg*m/s and (0,0,0) kg*m/s
After the interaction
(2.6x10^-21, 1.40x10^-21, 0) kg*m/s
and the other proton has to have a momentum that when added to this momentum equal the original value. Since the y and z vectors were initially 0, all we need for the y and x vector values of the result is to negate them. The x vector value will be
3.2x10^-21 - 2.6x10^-21 = 0.6x10^21 = 6.0x10^-22. So the other proton will have a momentum of
(6.0x10^-22, -1.40x10^-21, 0) kg*m/s</span>
A Many people who came to the hospital had very serious injuries.
Explanation:
From the passage, we can infer that many people who came to the hospital had very serious injuries.
Let us analyze the given options:
Many doctors were worried about the safety of their own families.
No where in the passage was the families of the Doctors mentioned. The passage directly spoke to the Doctors and their victims.
Many people were able to quickly leave the hospital after treatment.
There was shortage of blood and there was no way they could have been treated without it. The passage suggests an emergency situation was up.
Also, many people needed blood for treatment but there was an acute shortage. No way to treat and discharge them.
Many doctors who worked through the night wanted to go home.
Again, no text in the passage suggests this. We have a picture of Doctors who wanted to tend to their patients but lacked the means to do so.
<em>The fitting inference that can be drawn from the passage is that many people came to the hospital had serious injuries which led to blood shortage. </em>
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