Ask question

Ask question

All categories

3 years ago

15

Why you cannot use an elastic measuring tape to measure distance. What problem you may face if you use it

1 answer:

Stells [14]3 years ago

3 0

The problem you would encounter is measuring the height of two different people, a tall one and a short one, and getting the same answer for both of them.

No matter WHAT we're hearing out of the White House these days, you CAN'T bend and stretch your standard measuring devices, or any other 'facts', to make them fit the thing that you're measuring. This does not work. You're always entitled to your own opinions, but you're not entitled to your own facts.

You might be interested in

The gaps on Mendeleev's table _____.

larisa86 [58]

Represented elements not discovered in this time

6 0

3 years ago

What are the three main ways organisms interact?

Alexxx [7]

By communication, competition and symbiosis. These are the three main ways organisms interact.

7 0

4 years ago

Read 2 more answers

What tool could help a biologist study the movements of cells? digital camera with a zoom lens a satellite with a digital camera

Annette [7]

I think your answer would be (D) microscope with a video camera
Hope i helped!

4 0

3 years ago

Read 2 more answers

Which statements does the Second Law of Thermodynamics support?

Mazyrski [523]

According to the second law of thermodynamics,
the answer is
<span>4. The entropy of the universe is increasing. </span>

4 0

3 years ago

An object is thrown straight up into the air with an initial speed of 8 m/s, and reaches a greatest height of 15 m before it fal

Ugo [173]

Answer:

The value is $T_t = 2.5659 \ s$

Explanation:

From the we are told that

The initial speed of the object is $u = 8 \ m/s$

The greatest height it reached is $h = 15 \ m$

Generally from kinematic equation we have that

$v^2 = u^2 + 2gH$

At maximum height v = 0 m/s

So

$0^2 = 8^2 + 2 * - 9.8 * H$

=> $H = 3.27 \ m$

Here H is the height from the initial height to the maximum height

So the initial height is mathematically represented as

$s = h - H$

=> $s = 15 - 3.27$

=> $s = 11.73 \ m$

Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows

$v = u + (-g) t$

At maximum height v = 0 m/s

$0 = 8 - 9.8t$

=> $t = 0.8163 \ s$

Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows

$h = ut_1 + \frac{1}{2} gt_1^2$

Here the initial velocity is 0 m/s given that its the velocity at maximum height

Also g is positive because we are moving in the direction of gravity

So

$15 = 0* t + 4.9 t^2$

=> $t_1 = 1.7496$

Generally the total time taken is mathematically represented as

$T_t = t + t_1$

=> $T_t = 0.8163 + 1.7496$

=> $T_t = 2.5659 \ s$

6 0

3 years ago