Answer:
Explanation:
Given
Length of each wire 
On wire A second harmonic frequency is given by
where f=frequency
v=velocity of wave
L=length of wire
For wire B third harmonic is given by
Answer:
yes every action as an equal and and opposite reaction. if you throw a tool then it will give you a reaction and you will move back.
Explanation:
According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.
To understand it better:
Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude but in the opposite direction on the first.
So, if you as an astronaut in the described situation throw your tool in the direction that you are traveling (in the opposite direction of the space station), according to Newton's third law, you will be automatically moving towards the station
Answer:
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Explanation:
This scenario can be represented by an arithmetic progression AP.
nth term = a + nd
Where a is the first term given as 2.63 ft.
d is the common difference and is given as 5.3ft.
n is the particular second/time.
To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.
d = nth sum = (n/2)(2a+(n-1)d)
Where n = 10 seconds
a = 2.65 ft
d = 5.3 ft
Substituting the values we have;
d = (10/2)(2×2.65 + (10-1)5.3)
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
We have negative acceleration when an object projected upwards, while positive acceleration is a free fall.
To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.
The expression that defines the linear momentum is expressed as
P=mv
Where,
m=mass
v= velocity
According to our data we have to
v=10m/s
d=0.05m
Volume 
t = 3hours=10800s
From the given data we can calculate the volume of rain for 5 seconds
Where,
It is the period of time we want to calculate total rainfall, that is
Through water density we can now calculate the mass that fell during the 5 seconds:
Now applying the prevailing equation given we have to
Therefore the momentum of the rain that falls in five seconds is 
