Answer: 1.76 s
Explanation:
We have the following data:
is the total mass of the bike and the rider
is the initial velocity
is the force applied to the brakes
Firstly, we will find the acceleration
with the following equation:
(1)
Isolating
:
(2)
(3)
(4) This is the magnitude of the acceleration, however, since the final velocity is 0 m/s, this means the direction is negative
Hence:
(5)
On the other hand, with the following equation we can find the time
:
(6)
Where:
is the final velocity (the bike stops)
Isolating
:
(7)
(8)
Finally:
This iste time it takes to the bike to stop
Answer:
The acceleration of a car would be:
m/s²
Explanation:
Given
Initial velocity =
m/s
Final velocity =
m/s
Time elapsed =
s
To determine
We need to determine the acceleration of a car.
We know that acceleration is basically the rate of change in velocity over time.
Thus,
We can determine the acceleration using the formula

where
is the acceleration
is the initial velocity
is the final velocity
is time elapsed
now substituting the values
,
, and
in the formula



m/s²
Therefore, the acceleration of a car would be:
m/s²
The correct answer is: [A]: "TRUE" .
_________________________________________________
Answer:
From Wikipedia:
"A synovial joint, also known as diarthrosis, joins bones or cartilage with a fibrous joint capsule that is continuous with the periosteum of the joined bones, constitutes the outer boundary of a synovial cavity, and surrounds the bones' articulating surfaces. The synovial cavity/joint is filled with synovial fluid."
Answer:


Explanation:
<u>Given:</u>
Mass = m = 200,000 kg
Vertical Distance = h = 120 m
Speed = v = 14 m/s
Acceleration due to gravity = g = 10 m/s²
<u>Required:</u>
1) Gravitational Potential Energy = P.E = ?
2) Kinetic Energy = K.E. = ?
<u>Formula:</u>
1) P.E. = mgh
2) K.E. = 
<u>Solution:</u>
1) P.E. = (200,000)(10)(120)
P.E. = 240,000,000 Joules
P.E. = 240 Mega Joules
P.E. = 240 MJ
2) K.E. = 1/2 (200000)(14)^2
K.E. = (100000)(196)
K.E. = 19,600,000 Joules
K.E. = 19.6 MJ
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>