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11111nata11111 [884]
3 years ago
15

Heating glucose, a monosaccharide sugar, in the presence of excess oxygen produces carbon dioxide gas and water vapor. Balance t

his reaction. ___C6H12O6(s) + ___O2(g) → ___CO2(g) + ___H2O(g)
Chemistry
1 answer:
lozanna [386]3 years ago
6 0

Answer:

The balance reaction is C6H12O6+6O2=6CO2+6H2O

Explanation:

The reaction mentioned above is the reaction of cellular respiration.In this reaction glucose molecule reacts with oxygen to generate carbon dioxide,water and energy in form of ATP.

    In the left side there are 6 carbon atoms,12 hydrogen atoms and 18 oxygen atoms and the same number of carbon,hydrogen and oxygen is present in the right side of the reaction mentioned above.Thus the reaction can be balanced.

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I think that beryllium is formed in alcohol I think
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the ___is the area that allows us to pinpoint the location of pain, identify a texture and be aware of how our limbs are positio
vladimir1956 [14]

Answer:

The somatosensory cortex is a region of the brain which is responsible for receiving and processing sensory information from across the body, such as touch, temperature, and pain.

Area 1 specifically is important in sensing the texture of an object. :)

Hope this helps!

7 0
3 years ago
During which phase of the moon does a lunar eclipse occur?
Lelu [443]
Full moon
A lunar eclipse can occur only at full moon. A total lunar eclipse can happen only when the sun, Earth and moon are perfectly lined up — anything less than perfection creates a partial lunar eclipse or no eclipse at all.
3 0
2 years ago
What is the volume of 11.2 g of O2 at 7.78 atm and 415 K?
irina1246 [14]

Answer:

1.53 L

Explanation:

Step 1: Given data

  • Mass of oxygen (m): 11.2 g
  • Pressure (P): 7.78 atm
  • Temperature (T): 415 K
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L

3 0
3 years ago
You wish to measure the iron content of the well water on the new property you are about to buy. You prepare a reference standar
djverab [1.8K]

1.04 ⨯ 10^{-4} M

<h3>Explanation</h3>

<em>A</em> = <em>ε</em> \cdot l \cdot c by the Beer-Lambert law, where

  • <em>A</em> the absorbance,
  • l the path length,
  • <em>ε</em> the molar absorptivity of the solute, and
  • c concentration of the solution.

<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, l \cdot c is constant; l is inversely proportional to c. The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.

The 13.0 mL standard solution has a concentration of 5.17 ⨯ 10^{-4} M. Diluting it to 45.0 mL results in a concentration of 5.17 \times 10^{-4} \times \frac{13.0}{45.0} = 1.494 M.

c is inversely related to l for the two solutions. As a result, c₂ = c_1 \cdot \frac{l_1}{l_2} = 1.494 \times 10^{-4} \times \frac{1}{4.78} = 3.126 M.

The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of 3.126 \times \frac{100.0}{30.0} = 1.04 ⨯ 10^{-4} M.

6 0
3 years ago
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