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postnew [5]
3 years ago
10

A line in the hydrogen spectrum occurs at 434 nm. what is the frequency of this radiation in sec -1

Chemistry
1 answer:
Taya2010 [7]3 years ago
7 0
The lines occurring in an emission spectrum are all electromagnetic waves, which means that their speed in a vacuum is
3 x 10⁸ m/s


We can use the equation,
v = fλ
which relates the velocity of a wave to the frequency and wavelength. Substituting values,

3 x 10⁸ = f * 434 x 10⁻⁹
f = 6.91 x 10¹⁴ Hz

The frequency of the wave will be 6.91 x 10¹⁴ oscillations per second.
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Explanation :

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PV=nRT

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V = Volume of N_2 gas = 985 mL = 0.982 L    (1 L = 1000 mL)

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Now put all the given values in above equation, we get:

(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K

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Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains 6.022\times 10^{23} number of molecules.

As, 1 mole of N_2 gas contains 6.022\times 10^{23} number of molecules

So, 5.78\times 10^{-11} mole of N_2 gas contains (5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13} number of molecules

Therefore, the number of molecules present in nitrogen gas are, 3.48\times 10^{13}

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