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postnew [5]
3 years ago
10

A line in the hydrogen spectrum occurs at 434 nm. what is the frequency of this radiation in sec -1

Chemistry
1 answer:
Taya2010 [7]3 years ago
7 0
The lines occurring in an emission spectrum are all electromagnetic waves, which means that their speed in a vacuum is
3 x 10⁸ m/s


We can use the equation,
v = fλ
which relates the velocity of a wave to the frequency and wavelength. Substituting values,

3 x 10⁸ = f * 434 x 10⁻⁹
f = 6.91 x 10¹⁴ Hz

The frequency of the wave will be 6.91 x 10¹⁴ oscillations per second.
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C. 49.8 grams of ki is dissolved in enough water to make 1.00 l of solution. what is the molarity?
taurus [48]

Hey There!:


Molar Mass KI => 166.003 g/mol


* number of moles:


n = mass of solute / molar mass


n = 49.8 / 166.003


n = 0.3 moles KI


Therefore:


M = n / V


M = 0.3 / 1.00


M = 0.3 mol/L


hope this helps!

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SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
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3 years ago
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