Answer:
3Ag^(+) + 3Cl ^(-) --> 3AgCl (s)
Explanation:
Full ionic equation:
3Ag^(+) + 3NO3^(-) + Al^(+3) + 3Cl^(-)-->
3AgCl (s) + Al^(3+) + 3NO3^(-)
Spectator ions 3NO3^(-) & Al^(+3) can be left out in the net ionic equation.
B and d will work out and a and c will also work out
Answer is: 0,133 mol/ l· atm.
T(chlorine) = 10°C = 283K.
p(chlorine) = 1 atm.
V(chlorine) = 3,10 l.
R - gas constant, R = 0.0821 atm·l/mol·K.
Ideal gas law: p·V = n·R·T
n(chlorine) = p·V ÷ R·T.
n(chlorine) = 1atm · 3,10l ÷ 0,0821 atm·l/mol·K · 283K = 0,133mol.
Henry's law: c = p·k.
k - <span>Henry's law constant.
</span>c - solubility of a gas at a fixed temperature in a particular solvent.
c = 0,133 mol/l.
k = 0,133 mol/l ÷ 1 atm = 0,133 mol/ l· atm.
The answer would be, it would be warmer.
Explanation:
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