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Aloiza [94]
3 years ago
11

What do methanoic acid (HCOOH), 1-chloroethane (CH2ClCH3), and propanone (CH3COCH3) have in common?

Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0
Functional groups are the set of atoms in a compound that's responsible for the chemical properties of the compound. 
the functional groups for the given compounds are as follows
methanoic acid = carboxylic group 
chloroethane = haloalkane
propanone = ketone
option A is incorrect as only one of the given compounds is a carboxylic acid, others have other functional groups
option C is incorrect as they have three different functional groups as stated above 
option B is incorrect as its not a homologous series. Homologous series are a set of compounds with same functional group that differs by a CH₂ group. since the functional groups are different it does not belong to a homologous series as well . 

correct option is D. none of these
as none of the other options are correct 
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JulsSmile [24]

Answer:

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Explanation:

8 0
3 years ago
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Which has a greater density, a pound of feathers or a pound of gold
artcher [175]

Answer:

Explanation:

Hello!!

Please remember that density=mass/volume.

In this case, we have the same mass for the feathers and the gold (1 pound).

So, if the mass is the same for both we have:

Df*Vg=Dg*Vf    where f means feathers and g means gold.

In this case we see density is inversely related to volume. Both materials have the same mass. So which one have a bigger volume?

For this take a pound of feathers and submerge in a known volume of water. Note the displacement. Do the same for a pound of gold. Whichever has the smaller displacement, has the greater density.

In this case, Gold has the greatest density.

3 0
3 years ago
Based on the name, which substance is a covalent compound?
jek_recluse [69]
Compounds that has two elements on the formula can be bonded by ionic or covalent bond. If the compound is a metal and a non-metal then it will be ionic bonding. However, when it involves two non-metals, then it will have covalent bonding.
3 0
3 years ago
In the first step of hydroboration mechanism, why is an arrow drawn from the pi bond of the alkene to the B atom of the borane r
fomenos

Answer:

To fulfill octet of B atom in borane, nucleophilic attack by pi electrons of alkene takes place with electrophilic B center in borane.

Explanation:

In Borane (BH_{3}), B atom has energetically vacant 2p orbital and thereby octet is incomplete.Therefore B center in borane act as an electrophilic center.

In alkene, pi bonding electrons are loosely bound together due to side on overlap of two constituent p-orbitals. Hence this pi bond can be easily broken. Alternatively, we can say that pi bond in alkene act as a potential nucleophile.

The first step of hydroboration occurs in a concerted manner where pi electrons of alkene first attack vacant 2p orbital of B in borane to fulfill it's octet (represented by an arrow drawn from alkene to B atom) and forms a 4 memebered cyclic intermediate. Simulaneously, a B-H bond in borane is donated to alkene through 3c-2e bond (3 center-2 electron bond).

Full mechanism has been shown below.  

5 0
3 years ago
The Lewis dot structure for an isolated carbon atom has 1. two pairs of electrons and two lone electrons. 2. one pair of electro
likoan [24]
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Valence electrons are in 2s and 2p orbitals. There is one pair of electrons in 2s orbital and two lone electrons in 2p orbital with the same electron spin. Carbon is in group 14 of periodic table group.
3 0
3 years ago
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