What do methanoic acid (HCOOH), 1-chloroethane (CH2ClCH3), and propanone (CH3COCH3) have in common?

1 answer:

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Functional groups are the set of atoms in a compound that's responsible for the chemical properties of the compound.
the functional groups for the given compounds are as follows
methanoic acid = carboxylic group
chloroethane = haloalkane
propanone = ketone
option A is incorrect as only one of the given compounds is a carboxylic acid, others have other functional groups
option C is incorrect as they have three different functional groups as stated above
option B is incorrect as its not a homologous series. Homologous series are a set of compounds with same functional group that differs by a CH₂ group. since the functional groups are different it does not belong to a homologous series as well .

correct option is D. none of these
as none of the other options are correct

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1. In the first step of the mechanism for this process, a phenoxide anion is generated. This phenoxide anion goes on to act as a

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Answer:

See the explanation

Explanation:

In this case, in order to get an elimination reaction we need to have a strong base. In this case, the base is the phenoxide ion produced the phenol (see figure 1).

Due to the resonance, we will have a more stable anion therefore we will have a less strong base because the negative charge is moving around the molecule (see figure 2).

Finally, the phenoxide will attack the primary carbon attached to the Cl. The C-Cl bond would be broken and the C-O would be produced at the same time to get a substitution (see figure 1).