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Aloiza [94]
3 years ago
11

What do methanoic acid (HCOOH), 1-chloroethane (CH2ClCH3), and propanone (CH3COCH3) have in common?

Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0
Functional groups are the set of atoms in a compound that's responsible for the chemical properties of the compound. 
the functional groups for the given compounds are as follows
methanoic acid = carboxylic group 
chloroethane = haloalkane
propanone = ketone
option A is incorrect as only one of the given compounds is a carboxylic acid, others have other functional groups
option C is incorrect as they have three different functional groups as stated above 
option B is incorrect as its not a homologous series. Homologous series are a set of compounds with same functional group that differs by a CH₂ group. since the functional groups are different it does not belong to a homologous series as well . 

correct option is D. none of these
as none of the other options are correct 
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g A gas is compressed in a cylinder from a volume of 20.0 L to 2.0 L by a constant pressure of 10.0 atm. Calculate the amount of
Lemur [1.5K]

Answer:

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Explanation:

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

W system= -p*∆V

Where:

  • W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
  • p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
  • ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

  • p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)
  • ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)

Replacing:

W system= -1.013*10⁶ Pa* (-0.018 m³)

Solving:

W system= 18234 J

<u><em>The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.</em></u>

5 0
3 years ago
Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.
mamaluj [8]

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be sp^3 but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be sp^2.

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be sp^3.

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be sp^3d.

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be sp^3d^2.

6 0
3 years ago
Give the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by the element. rb
devlian [24]

Actually Rb or Rubidium in zero state has the following electron configuration:

<span>1s22s2</span><span>2p6</span><span>3s2</span><span>3p63d10</span><span>4s2</span><span>4p65s1</span>

 

However we can see that the ion has a 1 positive charge, which means that it lacks 1 electron, therefore the answer from the choices is:

<span>d. rb+: 1s22s22p63s23p64s23d104p6</span>
3 0
3 years ago
Which statement describes the use of a flowchart?
Crazy boy [7]

Answer:

idk i got 0 iQ

Explanation:

4 0
3 years ago
If you wanna get oil to 180 celcius when it starts at 20 how many units of thermal energy is needed?
Zarrin [17]

Answer:

The thermal energy (heat) needed, to raise the temperature of oil of mass  'm' kilogram and specific heat capacity 'c' from 20°C to 180°C  is  160·m·c joules

Explanation:

The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT

∴ C = ΔQ/ΔT

ΔQ = C × ΔT

C = m × c

Where;

c = The specific heat capacity

ΔT = The temperature change = T₂ - T₁

∴ ΔQ = m × c × ΔT

Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C  is given as follows;

ΔQ = m × c × (180° - 20°) = 160° × m·c

ΔQ = 160·m·c joules

7 0
3 years ago
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