Answer:
22.49 g of NH3
Explanation:
The balanced equation for this would be:
3H₂+N₂ → 2NH₃
So let's take note of this:
We will need 3 moles of H₂ to produce 2 moles of NH₃.
Now let us convert:
First we determine the molar mass of H2:
Element:
number of atoms x molar mass
H = 2 x 1.01 g/mol = 2.02 g/mol
Let's see how many moles of H2 there are in 4.00g

Now we can see how many moles of NH₃ we can make given the ratio and convert it again to grams by getting the molar mass of NH₃:

This means that with 1.98 moles of H₂, we produce 1.32 moles of NH₃
So let's get the molar mass of NH₃ so we can convert it to grams:
N = 1 x 14.01 = 14.01
H = 3 x 1.01 = 3.03
17.04g/mol

Division of lab our is the same thing as Specialization.
Since it’s a credit card you must subtract 330.19-50.00 = 280.19 then with the fine you add 280.19+4.20= 284.39. So the new balance is $284.39
Answer:
E). Use inexpensive digital marketing tools to inform the community about an upcoming fundraising event.
Explanation:
The 'use of inexpensive digital marketing tools for informing the community regarding the approaching fundraising event' would be the most appropriate and feasible for the non-profit organization as it would be the most reasonable for the firm. A big-budget expense on marketing the event would neither be affordable due to the small budget nor beneficial for such an organization. Thus, using inexpensive digital marketing would publicize the event on an affordable budget and prove helpful in gathering good collections in the event. Hence, <u>option E</u> is the correct answer.