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Delicious77 [7]
3 years ago
7

An ambulance is driving towards the hospital at a velocity 108 km/h and emitting a steady 798-Hz sound from its siren. The sound

reflects off the front of the hospital and is received by the same ambulance. In addition to it's own siren, the ambulance hears a shifted tone from the reflection at what frequency? The speed of sound on this day is 343 m/s. a. 1.06e+3Hz b. 855Hz c. 850Hz d. 1.08e+3Hz e. 950 Hz
Physics
1 answer:
slava [35]3 years ago
5 0

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. Mathematically it can be described as

f_d= f_s \frac{(v+v_d)}{(v-v_s)}

The meaning of each of these variables is,

v_d=Velocity of detector

f_s=Frequency of wave emitted by source

v_s=Velocity of source

v=Velocity of sound wave

f_d=Frequency received by detector

Replacing we have that,

f_d = 798(\frac{(343+30)}{(343-30)})

f_d=950 Hz

Therefore the correct option is e. 950Hz

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fomenos

To solve this problem it is necessary to apply the rules and concepts related to logarithmic operations.

From the definition of logarithm we know that,

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In this way for the given example we have that a logarithm with base 10 expressed in the problem can be represented as,

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We can express this also as,

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By properties of the logarithms we know that the logarithm of a power of a number is equal to the product between the exponent of the power and the logarithm of the number.

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3 years ago
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Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is
Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

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change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

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