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Delicious77 [7]
3 years ago
7

An ambulance is driving towards the hospital at a velocity 108 km/h and emitting a steady 798-Hz sound from its siren. The sound

reflects off the front of the hospital and is received by the same ambulance. In addition to it's own siren, the ambulance hears a shifted tone from the reflection at what frequency? The speed of sound on this day is 343 m/s. a. 1.06e+3Hz b. 855Hz c. 850Hz d. 1.08e+3Hz e. 950 Hz
Physics
1 answer:
slava [35]3 years ago
5 0

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. Mathematically it can be described as

f_d= f_s \frac{(v+v_d)}{(v-v_s)}

The meaning of each of these variables is,

v_d=Velocity of detector

f_s=Frequency of wave emitted by source

v_s=Velocity of source

v=Velocity of sound wave

f_d=Frequency received by detector

Replacing we have that,

f_d = 798(\frac{(343+30)}{(343-30)})

f_d=950 Hz

Therefore the correct option is e. 950Hz

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A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is
Umnica [9.8K]

The frequency of note C3 is 131 s^{-1}.

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

Frequency=\frac{speed of sound}{Wavelength of note}

Thus,

Frequency = \frac{343 m/s}{2.62 m} = 131 s^{-1}

So the frequency of note C3 is 131 s^{-1}.

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