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Delicious77 [7]
3 years ago
7

An ambulance is driving towards the hospital at a velocity 108 km/h and emitting a steady 798-Hz sound from its siren. The sound

reflects off the front of the hospital and is received by the same ambulance. In addition to it's own siren, the ambulance hears a shifted tone from the reflection at what frequency? The speed of sound on this day is 343 m/s. a. 1.06e+3Hz b. 855Hz c. 850Hz d. 1.08e+3Hz e. 950 Hz
Physics
1 answer:
slava [35]3 years ago
5 0

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. Mathematically it can be described as

f_d= f_s \frac{(v+v_d)}{(v-v_s)}

The meaning of each of these variables is,

v_d=Velocity of detector

f_s=Frequency of wave emitted by source

v_s=Velocity of source

v=Velocity of sound wave

f_d=Frequency received by detector

Replacing we have that,

f_d = 798(\frac{(343+30)}{(343-30)})

f_d=950 Hz

Therefore the correct option is e. 950Hz

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A rocket travels vertically at a speed of 1300 km/hr.1300 km/hr. The rocket is tracked through a telescope by an observer locate
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Answer:

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time after which the observation starts, t = 3 min.

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s=-93760 m

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Three astronauts guide a 100 kg asteroid safely away from their space capsule. The first astronaut pushes with a 35 N force dire
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The magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

The given parameters;

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  • <em>force by second astronaut = 35 N, at 45 degrees above x-axis</em>
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The resultant horizontal force applied by the three astronauts on the asteroid is calculated as;

Fₓ = 35cos(45) + 35cos(45) + 35cos(0)

Fₓ = 84.5 N

The rate at which the asteroid's velocity changes is calculated as;

F = ma = m\frac{\Delta v}{\Delta t} \\\\\frac{\Delta v}{\Delta t}  = \frac{F}{m} \\\\\frac{\Delta v}{\Delta t}  = \frac{84.5}{100} \\\\\frac{\Delta v}{\Delta t}  = 0.845 \ m/s^2

Thus, the magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

Learn more here: brainly.com/question/20407089

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