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REY [17]
3 years ago
12

¿Cuál es la diferencia entre un trauma físico y un trauma psicológico?

Physics
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer:

El estudio consistió en relacionar las características del proceso laboral, con las exigencias y los daños a la salud física y mental (trastornos psíquicos, psicosomáticos, musculoesqueléticos y accidentes) en las enfermeras de un hospital psiquiátrico infantil.

Explanation:

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Which benefit outweighs the risks in the technological design of headphones?
Dmitriy789 [7]

Answer:

The Answer is A They can damage hearing.

Explanation:

I took the Test

7 0
3 years ago
Which of the following statements about asteroids is true? A. The asteroids in our solar system are spread out uniformly and are
Dennis_Churaev [7]
<span>The majority of the asteroids in our solar system are found
in the space between the orbits of Mars and Jupiter. (B)</span>
7 0
2 years ago
Read 2 more answers
What is the product of the cellular respiration process
zlopas [31]
When oxygen is present, cellular respiration produces carbon dioxide, water, and energy in the form of ATP.

When oxygen is not present, cellular respiration produces lactic acid or alcohol.

Hope this helps! :)
4 0
3 years ago
A uniform rod of length 0.7 m and mass 10 kg rotates freely about a horizontal axis passing through one end of the rod a bullet
mars1129 [50]

Answer:

<u>ω = 1.7 rad/s</u>

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

3 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec
juin [17]

Answer:

Explanation:

Given that:

angular frequency = 11.3 rad/s

Spring constant (k) = = \omega^2  \times m

k = (11.3)² m

k = 127.7 m

where;

x_1 = 0.065 m

x_2  = 0.048 m

According to the conservation of energies;

E_1=E_2

∴

\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2

kx_1^2 = mv_2^2 + kx_2^2

(127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2

0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325  - 0.2942208 = v_2^2 \\ \\  v_2^2 = 0.2453117 \\ \\  v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}

4 0
3 years ago
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