3 years ago

A student walks to school at a speed of 1.2 m/s. if the students mass is 53kg, what is the students kinetic energy

1 answer:

3 0

Kinetic energy = 0.5 x mass x velocity squared
= 0.5 x 53 x (1.2)^2
38.16J

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Vladimir [108]

Explanation:

It is given that,

Force applied to object, $F=(2i+3j)\ N$

Position, $r=(4i+5j)\ m$

(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :

$\tau=F\times r$

$\tau=(2i+3j) \times (4i+5j)$

$\tau=\begin{pmatrix}0&0&-2\end{pmatrix}$

$\tau=(-2k)\ N-m$

The torque is acting in -z axis.

(a) The magnitude of torque is given by :

$|\tau|=\sqrt{(-2)^2}$

$|\tau|=2\ N-m$

Hence, this is the required solution.

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Taya2010 [7]

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kondor19780726 [428]

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Hope this helps

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3 years ago