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Tcecarenko [31]
3 years ago
10

A helicopter (m = 3250 kg) is cruising at a speed of 56.9 m/s atan altitude of 185 m. What is the total mechanical energy of the

helicopter?A) 6.91 x 107 JB) 5.26 x 107 JC) 1.12x 108 JD) 2.27 x 108 JE) 3.91 x 107 J
Physics
1 answer:
taurus [48]3 years ago
6 0

Answer:

The mechanical energy of the helicopter is 1.12\times 10^7\ J.

Explanation:

It is given that,

Mass of the helicopter, m = 3250 kg

Speed of the helicopter, v = 56.9 m/s

Position of the helicopter, h = 185 m

The energy possessed by an object due to its motion is called its kinetic energy. It is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 3250\times (56.9)^2  

E=5.26\times 10^6\ J

The energy possessed by an object due to its position is called its potential energy. It is given by :

E=mgh

E=3250\times 9.8\times 185  

E=5.89\times 10^6\ J

The sum of kinetic and potential energy is called mechanical energy of the system. It is given by :

M=5.26\times 10^6+5.89\times 10^6

M=11.15\times 10^6\ J

or

M=1.12\times 10^7\ J

So, the mechanical energy of the helicopter is 1.12\times 10^7\ J. Hence, this is the required solution.

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A 42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. It starts from rest at t = 0, and a line dr
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Answer:

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Explanation:

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The angular speed is 6.21 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=0.21\times 6.21\\\Rightarrow v=1.3041\ m/s

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

a_t=r\alpha\\\Rightarrow a_t=0.21\times 2.7\\\Rightarrow a_t=0.567\ m/s^2

Tangential acceleration is 0.567 m/s²

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In degress the angle would be

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From x axis it would be

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In order for the electron to escape, the energy of the absorbed photon must be exactly equal to the (negative) energy of the level in which the electron lies.

For an hydrogen atom, the energy levels are given by

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