The coefficient of expansion is 13 * 10^-6 m per meter length.per oK
The temperature difference = 42 - - 8 = 50 oC
delta T = (42 + 273) - (-8 + 273) = 50 oK
delta L = L * 13* 10^6 m/oK
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m
The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.
The number of electrons initially given to sphere A is

, and since the charge of 1 electron is

, the net charge left on sphere A after the removal of the rod will be
Answer:
The height of the water above the hole in the tank is 58 mm
Explanation:
In order to solve this problem we need to draw a sketch of the dimensions that include the input variables of the problem.
Where:
x = 0.579[m]
y = 1.45 [m]
Using the following kinematic equation we can find the time that takes the water to hit the ground, and then with this time, we can find the velocity of the water in the x-component.

It is necessary to clarify the value of each of the respective variables below
y = - 1.45 [m] "It is negative because this point is below the water outlet"
yo = 0
vo = 0 "The velocity is zero because the component of the speed on the Y-axis does not exist"
therefore:
![-1.45=0.5*(-9.81)*t^{2} \\t = \sqrt{\frac{1.45}{0.5*9.81} } \\t = 0.543[s]](https://tex.z-dn.net/?f=-1.45%3D0.5%2A%28-9.81%29%2At%5E%7B2%7D%20%5C%5Ct%20%3D%20%5Csqrt%7B%5Cfrac%7B1.45%7D%7B0.5%2A9.81%7D%20%7D%20%5C%5Ct%20%3D%200.543%5Bs%5D)
The next step is to determine the velocity in component x, knowing the time.
![v=\frac{x}{t} \\v=\frac{0.579}{.543} \\v = 1.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5Cv%3D%5Cfrac%7B0.579%7D%7B.543%7D%20%5C%5Cv%20%3D%201.06%5Bm%2Fs%5D)
Now using torricelli's law we can find the elevation.
![v=\sqrt{2*g*h} \\h=\frac{v^{2} }{2*g} \\h=\frac{1.06^{2} }{2*9.81} \\h= 0.057[m] = 57.95[mm]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%2Ag%2Ah%7D%20%5C%5Ch%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7B2%2Ag%7D%20%5C%5Ch%3D%5Cfrac%7B1.06%5E%7B2%7D%20%7D%7B2%2A9.81%7D%20%5C%5Ch%3D%200.057%5Bm%5D%20%3D%2057.95%5Bmm%5D)
The actual weight of the stone is 11 N. It is based on the Archimedes principles.
<h3>What is Archimedes principle?</h3>
- Archimedes principle states that the up thrust by water on an object is equal to the weight of water displaced.
- Upthrust by water on an object= actual weight of object - weight inside water
<h3>What is the actual weight of the object, if its weight inside water is 9N and weight of water displaced is 2N?</h3>
Actual weight= weight inside water+ weight of water displaced
= 9N + 2N = 11N
Thus, we can conclude that the actual weight of the object is 11N.
Learn more about the Archimedes principle here:
brainly.com/question/775316
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The frequency of the radio waves from the fm station is:

And the speed of the waves corresponds to the speed of light:

Therefore, the wavelength of the radio waves can be found by using the following equation: