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Arada [10]
3 years ago
8

A mixture contains methane (CH4), ethane (C2H6), and propane (C3H8). The mixture contains 25.9% methane, 31.4% ethane, and the b

alance propane by mass. Converting the mass percents to mole fractions for all three components gives:
Chemistry
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

Mol fraction methane = 0.4453

Mol fraction ethane = 0.2878

Mol fraction propane = 0.2669

Explanation:

Step 1: Data given

Suppose the mass of the mixture = 100 grams

The mixture contains:

25.9 % methane = 25.9 grams

31.4 % ethane = 31.4 grams

propane = 100 - 25.9 - 31.4 = 42.7 grams

Molar mass of methane = 16.04 g/mol

Molar mass of ethane = 30.07 g/mol

Molar mass of propane = 44.1 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles methane = 25.9 grams / 16.04 g/mol

Moles methane = 1.615 moles

Moles ethane = 31.4 grams / 30.07 g/mol

Moles ethane = 1.044 moles

Moles propane = 42.7 grams / 44.1 g/mol

Moles propane = 0.968 moles

Step 3: Calculate total moles

Total moles = moles methane + moles ethane + moles propane

Total moles = 1.615 + 1.044 + 0.968

Total moles = 3.627 moles

Step 4: Calculate mo lfraction

Mol fraction = mol component / total moles

Mol fraction methane = 1.615 moles/ 3.627 moles

Mol fraction methane = 0.4453

Mol fraction ethane = 1.044 moles / 3.627 moles

Mol fraction ethane = 0.2878

Mol fraction propane = 0.968 moles / 3.627 moles

Mol fraction propane = 0.2669

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anastassius [24]
Hey there!

Density = 2.70 g/cm³

Volume = 10.0 cm³

Therefore:

Mass = density *  volume

Mass = 2.70 * 10.0

Mass = 27.0 g
3 0
3 years ago
A researcher wants to determine if a unicellular organism he discovered is an autotroph or a heterotroph. He radioactively label
GaryK [48]

Answer:

A

Explanation:

Autotrophs utilize the energy from  sunlight to reduce carbon dioxide to carbohydrates (glucose). The energy from the sunlight is used to split water into H+ and O2- and the H+ used in the reduction process. The labeled carbon in the carbon dioxide will, therefore, be incorporated by the autotrophs in the carbohydrates made in photosynthesis.  

4 0
2 years ago
Which response has both answers correct? Will a precipitate form when 250 mL of 0.33 M Na 2CrO 4 are added to 250 mL of 0.12 M A
olchik [2.2K]

Answer:

A precipitate will form.

[Ag⁺] = 2.8x10⁻⁵M

Explanation:

When Ag⁺ and CrO₄²⁻ are in solution, Ag₂CrO₄(s) is produced thus:

Ag₂CrO₄(s) ⇄ 2 Ag⁺(aq) + CrO₄²⁻(aq)

Ksp is defined as:

Ksp = 1.1x10⁻¹² = [Ag⁺]² [CrO₄²⁻]

<em>Where the concentrations [] are in equilibrium</em>

Reaction quotient, Q, is defined as:

Q = [Ag⁺]² [CrO₄²⁻]

<em>Where the concentrations [] are the actual concentrations</em>

<em />

If Q < Ksp, no precipitate will form, if Q >= Ksp, a precipitate will form,

The actual concentrations are -Where 500mL is the total volume of the solution-:

[Ag⁺] = [AgNO₃] = 0.12M ₓ (250mL / 500mL) = 0.06M

[CrO₄²⁻] = [Na₂CrO₄] = 0.33M × (250mL / 500mL) = 0.165M

And Q = [0.06M]² [0.165M] = 5.94x10⁻⁴

As Q > Ksp; a precipitate will form

In equilibrium, some Ag⁺ and some CrO₄⁻ reacts decreasing its concentration until the system reaches equilibrium. Equilibrium concentrations will be:

[Ag⁺] = 0.06M - 2X

[CrO₄²⁻] = 0.165M - X

<em>Where X is defined as the reaction coordinate</em>

<em />

Replacing in Ksp expression:

1.1x10⁻¹² = [0.06M - 2X]² [0.165M - X]

Solving for X:

X = 0.165M → False solution. Produce negative concentrations.

X = 0.0299986M

Replacing, equilibrium concentrations are:

[Ag⁺] = 0.06M - 2(0.0299986M)

[CrO₄²⁻] = 0.165M - 0.0299986M

<h3>[Ag⁺] = 2.8x10⁻⁵M</h3>

[CrO₄²⁻] = 0.135M

6 0
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Natalija [7]

Answer:

true

Explanation:

6 0
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nata0808 [166]
Empirical formula is the simplest way the molecular formula can be wrote so here 7 goes into all of these so it would be CH2O
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