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Andre45 [30]
3 years ago
14

The electric field in a region of space increases from 0 0 to 3450 N/C 3450 N/C in 4.40 s. 4.40 s. What is the magnitude of the

induced magnetic field B B around a circular area with a diameter of 0.460 m 0.460 m oriented perpendicularly to the electric field?

Physics
1 answer:
slavikrds [6]3 years ago
7 0

Answer: B = 1380T

Explanation: please find the attached file for the solution

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PLEASE HELP THIS IS TIMED I WILL PICK YOU THE BRAINLIEST!!!!!!!!!!!How are secondary colors of light related to the primary colo
Kipish [7]

Explanation:

Because combining primary colors od light like red, blue, and green created secondary colors like yellow, cyan, and magenta

4 0
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the presence of which magnetic feature best explains why a magnet can act a distance on other magnets or on objects containing c
katen-ka-za [31]

Magnetic fields

Explanation:

The presence of magnetic fields  best explains why a magnet can act a distance on other magnets or on objects containing certain metals.

  • Magnetic fields are lines of forces around a bar magnet.
  • These lines of forces attracts and repels other magnetic bodies and metallic bodies round it.
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8 0
3 years ago
As the distance between two objects decreases, the pull of gravity
aliya0001 [1]

Answer: increases

Explanation:

Because the relationship between hand d is counter

6 0
3 years ago
What is the longest wavelength of light that will emit electrons from a metal whose work function is?
alexdok [17]
 Best Answer:<span>  </span><span>hf = work function + KE 
However if you are looking at the max wavelength (or threshold frequency) then there will only be just enough energy for the photoelectrons to be liberated, hence their KE will be 0. 
So hf = work function 
convert eV to joules, 2.4 x (1.6 x 10^-19) = 3.84 x 10^-19 
therefore, hf = 3.84 x 10^-19 
f = 3.84 x 10^-19 / planck's constant which is 6.63 x 10^-34 
f = 5.79 x 10^14 Hz 
c = frequency x wavelength, 
wavelength = speed of light/frequency 
= (3x10^8)/(5.79x10^14) 
=5.18 x 10^-7 metres</span>
6 0
3 years ago
A cylindrical rod of length L is connected across a fixed potential difference, creating a current I through the rod. What would
Inessa05 [86]

Answer:

The value of current through the rod becomes half

i' = \frac{i}{2}

Explanation:

As per Ohm's law we know that the current through a resistor is given as

i = \frac{V}{R}

here we know that

R = \rho \frac{L}{A}

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

i = \frac{V A}{\rho L}

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same

so we will have

i' = \frac{VA}{\rho (2L)}

now from above two equations we have

\frac{i}{i'} = 2

so new current will become

i' = \frac{i}{2}

3 0
3 years ago
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