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Andre45 [30]
3 years ago
14

The electric field in a region of space increases from 0 0 to 3450 N/C 3450 N/C in 4.40 s. 4.40 s. What is the magnitude of the

induced magnetic field B B around a circular area with a diameter of 0.460 m 0.460 m oriented perpendicularly to the electric field?

Physics
1 answer:
slavikrds [6]3 years ago
7 0

Answer: B = 1380T

Explanation: please find the attached file for the solution

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Answer b protons and electrons
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Laskar, J.: 1990, The chaotic motion of the solar system. A numerical estimate of the size of the chaotic zones, Icarus, 88, 266
balandron [24]

The chaotic nature of the Solar System excluding Pluto was established by the numerical computation of the maximum Lyapunov exponent of its secular system over 200 myr.

<h3>What is chaotic motion of the solar system ?</h3>

There has been an increase in awareness of chaotic dynamics in the solar system over the past 20 years. The orbits of tiny objects in the solar system, such as asteroids, comets, and interplanetary dust, are now known to be chaotic and to experience significant variations across geological time periods.

  • a completely unpredictable orbit, or one where significant changes in the orbit can result from even small changes in the position and/or velocity of the orbiting entity.

Learn more about Chaotic motion here:

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1 year ago
First right answer gets brainly<br><br>What is the speed of a man who runs 14 miles in 144 minutes?
andreev551 [17]

Answer:

10 mph

Explanation:

7 0
3 years ago
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
3 years ago
A heat engine: A) converts heat input to an equivalent amount of workB) converts work to an equivalent amount of heat C) takes h
Masja [62]

Answer:

C. Takes heat in, does work, and loses energy heat.

Explanation:

Heat engine is a system makes use of thermal energy (heat) to in order to do mechanical work.

This occurs by converting the heat into mechanical energy. This energy is then used to do work.

The key characteristic of a heat engine is that the substance with which work is done by, goes from a higher temperature to a lower temperature.

Hence, it loses heat as it does work.

3 0
3 years ago
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