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2 years ago

The component that allows a car to execute complex maneuvers is __________ .

1 answer:

6 0

The anti-lock braking system (ABS) is a car component that enables the driver to execute complex maneuvers. Furthermore, it allows shifting the position of your car when driving on highways because of its ability to "maintain traction." It also can decrease the kinetic energy of your car when you want to make it decelerated.

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A 50kg box is pulled on by a rope. The rope applies a horizontal force of 180 N to the box. What is the normal force exerted on

Over [174]

The normal force would be the opposing and equal force to gravity ... that is why the box isn't floating or going through the ground ... this is Newton's third law of motion

4 0

3 years ago

the volume of a water tank is 5m×4m×2m. If the tank is half filled with water. calculate the pressure exerted at the bottom of t

Natali5045456 [20]

Answer:

10⁴ Pa

Explanation:

Volume = 5m * 4m * 2m

When the tank is half filled ,

Volume = 5m * 4m * 1m = 20m³

Also we know that ,

Density of water = 10³ kg/ m³

$\longrightarrow$ Density = Mass/Volume

$\longrightarrow$ 10³ kg/m³ = m/20m³

$\longrightarrow$ m = 2 * 10⁴ kg

So that ,

$\longrightarrow$ Weight = mg

$\longrightarrow$ F = 2*10⁴ × 10 N

$\longrightarrow$ F = 2 * 10⁵ N

And ,

$\longrightarrow$ Pressure = Force/Area

$\longrightarrow$ P = 2 *10⁵/ 5 * 4 Pa

$\longrightarrow$ P = 10⁴ Pa

5 0

2 years ago

SOMEONE PLS PLS

Annette [7]

Answer:

wood ,clay brick ,aluminum, and copper.

Explanation:

7 0

2 years ago

A spring whose spring constant is 270 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required

cricket20 [7]

Answer:

0.02585 BTU

Explanation:

Given: Spring constant, k = 270 lbf/in

Initial force, f =100 lbf

Compression, x = 1 in

Work done can be calculated as follows:

$W = \int {(f+kx)} \, dx \\W = fx + \frac{1}{2}kx^2\\W= (100 lbf)(1 in)+ \frac{1}{2}(270 lbf/in)(1 in)^2\\W= 100+135 = 235 lbf in\\W=235 \times 0.00011 BTU = 0.02585 BTU$

6 0

3 years ago

An upright object 2.80 cm tall is placed 16.0 cm away from the vertex of a concave mirror with a center of curvature of 24.0 cm.

horrorfan [7]

Answer:

f = 12 cm

Explanation:

Center of Curvature:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of mirror.

The Radius of Curvature:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of mirror. It is the distance from pole to the center of curvature.

Focal Length:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

$f = \frac{R}{2}$

where,

f = focal length = ?

R = Radius of curvature = 24 cm

Therefore,

$f = \frac{24\ cm}{2}$

f = 12 cm

8 0

2 years ago