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Schach [20]
3 years ago
9

PL-1) A spring that hangs vertically is 25 cm long when no weight is attached to its lower end. Steve adds 250 g of mass to the

end of the spring, which stretches to a new length of 37 cm. What is the spring constant, k, in N/m?
Physics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

20.42 N/m

Explanation:

From hook's law,

F = ke ......................... Equation 1

Where F = Force applied to the spring., k = spring constant, e = extension.

Make k the subject of the equation,

k = F/e ................. Equation 2

Note: The force on the spring is equal to the weight of the mass hung on it.

F = W = mg.

k = mg/e................ Equation 3

Given: m = 250 g = 0.25 kg, e = 37-25 = 12 cm = 0.12 m.

Constant: g = 9.8 m/s²

Substitute into equation 3

k = (0.25×9.8)/0.12

k = 20.42 N/m.

Hence the spring constant = 20.42 N/m

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A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. Suppose at f
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Answer:

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Explanation:

Hello!

First we need to know how much an inch equals in nanometers and a day in seconds:

Since <em>1inch = 2.54cm</em> and <em>1cm=10^7nm</em>

<em>      </em>1 inch = 2.54 * 10^7 nm<em> </em>

<em />

Also <em>1day = 24hours = 24*60minutes = 24*60*60seconds</em>

<em>    </em>1 day = 86.4 * 10^3 s

Therefore the rate at which the hair grows in nanometers per seconds is:

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Now, if 1 atomic layer = 0.1 nm this means that 1 nm = 10 atomic layers.

Therefore:

The rate in atomic layers is

11.306 nm/s = 11.306 (10 atomic layers)/s = 113.06 atomic layers/sec

<em />

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