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lions [1.4K]
3 years ago
5

What factors contribute to global winds identify areas where winds are weak

Physics
2 answers:
vodka [1.7K]3 years ago
5 0
<span>The factors that influence wind and contribute to global winds are pressure gradient, Rossby waves and jet streams, and local weather conditions.</span>
Gennadij [26K]3 years ago
5 0
The factors that influence wind and contribute to world<span> winds </span>are<span> the pressure gradient, Rossby waves and jet streams, </span>and native climate<span>. </span>additionally<span>, the wind is controlled by the combined forces of pressure gradient, the </span>result<span>, and friction.
T</span>he 2<span> factors that cause the wind to deviate </span>are<span> horizontal pressure gradient that is</span> that the propulsion<span> behind wind, </span>and also the result that<span> is what shifts wind direction.
The </span>Coriolis force<span> caused by the Earth's rotation is what offers winds among aggressive </span><span>systems their </span>dextral <span>circulation </span>within the northern hemisphere because the<span> wind moves outward and is deflected right from </span>the middle<span> of </span>the air mass<span>. The pressure begins to fall </span>quicker whereas<span> the wind speed </span>at the same time will increase<span>.</span>
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The universal law of gravitation states that the force of attraction between two objects depends on which quantities?
Ronch [10]

Answer:

D. the masses of the objects and the distance between them

Explanation:

Gravitation is a force, a force doesn't care about the shape or density of objects, only about their masses... and distances.

And you can get it using the following equation:

f = \frac{Gm_{1}m_{2} }{d^{2} }

Where :

G is the universal gravitational constant : G = 6.6726 x 10-11N-m2/kg2

m represent the mass of each of the two objects

d is the distance between the centers of the objects.

4 0
3 years ago
Fluid originally flows through atube at a rate of 200 cm3/s. Toillustrate the sensitivity of the Poiseuille flow rate to various
Alexxx [7]

Answer:

Q_{2}=1200cm^{3}/s

Explanation:

Given data

Q₁=200cm³/s

We know that:

F=n\frac{vA}{l}\\

can be written as:

ΔP=F/A=n×v/L

And

Q=ΔP/R

As

n₂=6.0n₁

So

Q=ΔP/R

Q=\frac{nv}{lR}\\ \frac{Q_{2}}{n_{2}}= \frac{Q_{1}}{n_{1}}\\ Q_{2}=\frac{Q_{1}}{n_{1}}*(n_{2})\\Q_{2}=\frac{200}{n_{1}}*6.0n_{1}\\ Q_{2}=1200cm^{3}/s

3 0
3 years ago
A bucket of water of mass 10 kg is pulled at constant velocity up to a platform 30 meters above the ground. This takes 10 minute
Rudik [331]

Answer:

W = 2352 J

Explanation:

Given that:

  • mass of the bucket, M = 10 kg
  • velocity of pulling the bucket, v = 3m.min^{-1}
  • height of the platform, h = 30 m
  • time taken, t = 10 min
  • rate of loss of water-mass, m = 0.4 kg.min^{-1}

Here, according to the given situation the bucket moves at the rate,

v=3 m.min^{-1}

The mass varies with the time as,

M=(10-0.4t) kg

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

∆x =  3∆t meters

So, during this interval change in work done,

∆W = m.g∆x

<u>For work calculation:</u>

W=\int_{0}^{10} [(10-0.4t).g\times 3] dt

W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}

W= 2352 J

5 0
3 years ago
Why is visual constancy important?
weqwewe [10]

Answer:

C.

Explanation:

Visual constancy is a key mechanism that allows the perception to remain.the same even as images change

#<em><u>CARRYONLEARNING</u></em>

4 0
2 years ago
A satellite of mass m circles the earth a distance R from the center of the earth.If the radius of the earth is 6.0*10^6ms.calcu
Rom4ik [11]

(a) The height above the earth's surface of the parking orbit is determined from the difference between the orbital radius and earth's radius (h = r - R).

(b) Velocity of the satellite of the earth is determined with a formula given as  (2π/T)r.

<h3>Height above the earth's surface </h3>

The height above the earth's surface is calculated using the following formula;

T = \frac{2\pi r^{\frac{3}{2} }}{\sqrt{Gm} }

where;

  • T is time period of the satellite
  • r is orbital radius

r = h + R

h = r - R

where;

  • h is height above the earth's surface
  • R is radius of earth
<h3>Velocity of the satellite</h3>

The velocity of the satellite is determined using the formula below;

v = ωr

v = (2π/T)r

Learn more about velocity of satellite here: brainly.com/question/22247460

#SPJ1

5 0
2 years ago
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