Answer:
1275J
Explanation:
Given parameters:
Force on box = 85N
Distance moved = 15m
Unknown:
Work done = ?
Solution:
Work done is the amount of force applied on a body to move it through a specific distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 85 x 15 = 1275J
Uneven heating of land and sea causes warm air over land to rise up, creating a low pressure zone. So wind blows in from the sea to fill this low pressure zone
Answer:8 m/s
Explanation:
Given
kinetic Energy of
initially is at rest and let say is moving with velocity u
kinetic Energy of
In Completely inelastic collision both mass stick together and move with common velocity
Suppose v is the common velocity
therefore Final velocity with which both blocks moves is 1 m/s
Answer:
1. the electric potential energy of the electron when it is at the midpoint is - 2.9 x J
2. the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge is - 5.04 x J
Explanation:
given information:
= 3 nC = 3 x C
= 2 nC = 2 x C
r = 50 cm = 0.5 m
the electric potential energy of the electron when it is at the midpoint
potential energy of the charge, F
F = k
where
k = constant (8.99 x )
electron charge, = - 1.6 x C
since it is measured at the midpoint,
r =
= 0.25 m
thus,
F =
= k + k
= ()
= (8.99 x )( - 1.6 x )(3 x +2 x )/0.25
= - 2.9 x J
the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge
= 10 cm = 0.1 m
= 0.5 - 0.1 = 0.4 m
F = k + k
= (+)
= (8.99 x )( - 1.6 x )(3 x /0.1+2 x /0.4)
= - 5.04 x J
Answer:
The value is
Explanation:
From the question we are told that
The weight of the block is
The dimension of the block is
Generally two atmosphere is equivalent to
Generally 1 atm =
The area of the block would be evaluated using width and height because we need for the smaller surface to be in contact with the ground in order to maximize the pressure and minimize number of blocks
So
=>
Generally the force due to this blocks is mathematically represented as
Here N is the number of blocks
So
=>