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grin007 [14]
4 years ago
14

An inventor claims to have devised a cyclical engine for use in space vehicles that operates with a nuclear fuel generated energ

y source whose temperature is 510 K and sink at 270 K that radiates waste heat to deep space. He also claims that this engine produces 4.1 kW while rejecting heat at a rate of 15,000 kJ/h. Is this claim valid?
Engineering
1 answer:
slava [35]4 years ago
6 0

Answer:

Inventor claim is not valid.

Explanation:

Given that

Source temperature = 510 K

Sink temperature = 270 K

Power produce = 4.1 KW

Heat reject = 15,000 KJ/h

Heat reject =4.16 KW

As we know that

Heat addition = Heat rejection + Power produce

Heat addition = 4.16 + 4.1 KW

Heat addition = 8.16 KW

So efficiency of engine

\eta =\dfrac{Power\ produces}{heat\ added}

\eta =\dfrac{4.1}{8.16}

\eta =0.502

Now check the maximum efficiency can be possible by using Carnot heat engine

As we know that efficiency of Carnot heat engine given as

\eta =1-\dfrac{T_L}{T_H}

By putting the value

\eta =1-\dfrac{T_L}{T_H}

\eta =1-\dfrac{270}{510}

\eta =0.47

So the efficiency of Carnot cycle is less than the efficiency of above given engine.So this engine is not possible.It means that inventor claim is not valid.

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musickatia [10]

Answer:

<em>screw thrust = ML</em>T^{-2}<em> </em>

Explanation:

thrust of a screw propeller is given by the equation = pV^{2}D^{2} x \frac{ND}{V}Re

where,

D is diameter

V is the fluid velocity

p is the fluid density

N is the angular speed of the screw in revolution per second

Re is the Reynolds number which is equal to  puD/μ

where p is the fluid density

u is the fluid velocity, and

μ is the fluid viscosity = kg/m.s = ML^{-1}T^{-1}

<em>Reynolds number is dimensionless so it cancels out</em>

The dimensions of the variables are shown below in MLT

diameter is m = L

speed is in m/s = LT^{-1}

fluid density is in kg/m^{3} = ML^{-3}

N is in rad/s = LL^{-1}T^{-1} =

If we substitute these dimensions in their respective places in the equation, we get

thrust = ML^{-3}(LT^{-1}) ^{2}L^{2}\frac{T^{-1} L}{LT^{-1} }

= ML^{-3}L^{2}T^{-2}

<em>screw thrust = ML</em>T^{-2}<em> </em>

This is the dimension for a force which indicates that thrust is a type of force

6 0
3 years ago
A viscometer may be created by using a pair of closely fitting concentric cylinders and filling the gap between the cylinder wit
kari74 [83]

Answer:

The viscosity of the fluid is 6.05 Pa-s

Explanation:

The viscosity obtained from a rotating type viscometer is given by the equation

\mu =\frac{3Tt}{2\pi \omega R_o(R_o^3-R_i^3)}

where

T is the torque applied in the viscometer

't' is the thickness of gap

\omega is the angular speed of rotation

R_o,R_i are the outer and the inner raddi respectively

Since it is given that

\omega =100rpm=\frac{100\times 2\pi }{60}=10.47rad/sec

Applying the values in the above relation we get

\mu =\frac{3\times 0.021\times 0.02\times 10^{-3}}{2\pi \times 10.47\times 37.5\times 10^{-3}(37.52^3-37.5^3)\times 10^{-9}}=6.04Pa-s

5 0
3 years ago
Suppose within your web browser you click on a link to obtain a web page. The IP address for the associated URL is already cache
aleksandrvk [35]

Answer:

All the detailed steps are mentioned in pictures.

Explanation:

See attached pictures.

8 0
3 years ago
Carbon dioxide at 20°C flows in a pipe at a rate of 0.005 kg/s. Determine the minimum diameter required if the flow is laminar (
Vesna [10]

Answer:

the required diameter is 0.344 m

Explanation:

given data:

flow is laminar

flow of carbon dioxide Q = 0.005 Kg/s

for  flow to be laminar,  Reynold's number must be less than 2300 for pipe flow and it is given as

\frac{\rho VD}{\mu }

arrange above equation for diameter

\frac{\rho Q D}{\mu A }<2300

dynamic density of carbon dioxide = 1.47×10^{-5} Pa sec

density of carbon dioxide is 1.83 kg/m³

\frac{1.83\times 0.0056\times D}{1.47\times 10^{-5}\times \frac{\pi}{4} \times D^{2} }

\frac{1.83\times 0.0056}{1.47\times 10^{-5}\times \frac{\pi}{4} \times 2300}= D

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4 0
3 years ago
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ELEN [110]

Answer:

The correct option is;

C. Both A and B

Explanation:

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The power steering pumps which supply the power that to the fluid that eases steering of the wheel can be driven by the engine through a belt and pulley system or it can be installed in the front of the vehicle and from there, electrically driven alongside the refrigerant compressor

Therefore, both Technician A and Technician B are correct

7 0
3 years ago
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