Suppose within your web browser you click on a link to obtain a web page. The IP address for the associated URL is already cache
d in your local host, so there is no DNS look-up. Let RTT denotes the round trip time between the local host and the server containing the web page. Suppose the HTML file references three very small objects on the same server.
Neglecting transmission time, how much time elapses with from when the client clicks on the link until the client receives the object?
Neglecting transmission time, how much time elapses with from when the client clicks on the link until the client receives the object?
1 answer:
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Answer:
a) 358.8K
b) 181.1 kJ/kg.K
c) 0.0068 kJ/kg.K
Explanation:
Given:
P1 = 100kPa
P2= 800kPa
T1 = 22°C = 22+273 = 295K
q_out = 120 kJ/kg
∆S_air = 0.40 kJ/kg.k
T2 =??
a) Using the formula for change in entropy of air, we have:
∆S_air =
Let's take gas constant, Cp= 1.005 kJ/kg.K and R = 0.287 kJ/kg.K
Solving, we have:
[/tex] -0.40= (1.005)ln\frac{T_2}{295} ln\frac{800}{100}[/tex]
Solving for T2 we have:
Taking the exponential on the equation (both sides), we have:
[/tex] T_2 = e^5^.^8^8^2^8 = 358.8K[/tex]
b) Work input to compressor:
= 184.1 kJ/kg
c) Entropy genered during this process, we use the expression;
Egen = ∆Eair + ∆Es
Where; Egen = generated entropy
∆Eair = Entropy change of air in compressor
∆Es = Entropy change in surrounding.
We need to first find ∆Es, since it is unknown.
Therefore ∆Es =
∆Es = 0.4068kJ/kg.k
Hence, entropy generated, Egen will be calculated as:
= -0.40 kJ/kg.K + 0.40608kJ/kg.K
= 0.0068kJ/kg.k
Answer:
,
,
Explanation:
Let suppose that fluid is incompressible and diffuser works at steady state. A diffuser reduces velocity at the expense of pressure, which can be modelled by using the Principle of Mass Conservation:
The following relation are found:
The new relationship is determined by means of linear interpolation:
After some algebraic manipulation, the following for the velocity as a function of position is obtained hereafter:
The acceleration can be calculated by using the following derivative:
The derivative of the velocity in terms of position is:
The expression for acceleration is derived by replacing each variable and simplifying the resultant formula.