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3 years ago

1. What is the name of the covalent compound CCl4?2. What is the name of the covalent compound N2O5?

2 answers:

6 0

The first one, is like methane (CH4) but with 4 chlorine atoms. So tetrachloromethane. (Tetra is the Greek prefix for ‘four’)
The second one is a compound that consists of covalent bonds. This means that you should work with prefixes. This results in dinitrogenpent(a)oxide.

mr_godi [17]3 years ago

5 0

Answer:

It's carbon tetrachloride.

It's Dinitrogen Pentoxide.

Hope this helped!!!

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Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago

2 Holts

Luda [366]

A. They are the most destructive earthquake waves.

D. They can move in a rolling pattern through rock, like an ocean wave.

Explanation:

Surface waves are seismic waves that cause the most destruction during an earthquake.

Rayleigh waves are known to cause rolling pattern of rocks just like an ocean waves.

Seismic waves are elastic waves that notably transmits energy.
They usually accompany earthquakes.
There are two broad categories of these waves.
Surface and body waves.
Seismic surface waves are low frequency and long wavelength waves.
They travel very close to the surface.
They are made up of Love and Rayleigh waves.
Love waves travels laterally in a horizontal fashion.
Rayleigh waves rolls like ocean waves in the ground.
The bulk of the destruction caused during an earthquakes is due to these waves.
They are the last waves to arrive a seismic station

learn more:

Seismograph brainly.com/question/11292835

#learnwithBrainly

7 0

3 years ago

Zinc and magnesium metal each reacts with hydrochloric acid to make chloride salts of the respective metals, and hydrogen gas. a

kirill115 [55]

M=11.20 g
m(H₂)=0.6854 g
M(H₂)=2.016 g/mol
M(Mg)=24.305 g/mol
M(Zn)=65.39 g/mol
w-?

m(Mg)=wm
m(Zn)=(1-w)m

Zn + 2HCl = ZnCl₂ + H₂
m₁(H₂)=M(H₂)m(Zn)/M(Zn)=M(H₂)(1-w)m/M(Zn)

Mg + 2HCl = MgCl₂ + H₂
m₂(H₂)=M(H₂)m(Mg)/M(Mg)=M(H₂)wm/M(Mg)

m(H₂)=m₁(H₂)+m₂(H₂)
m(H₂)=M(H₂)(1-w)m/M(Zn)+M(H₂)wm/M(Mg)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

m(H₂)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

(1-w)/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

1/M(Zn)-w/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

w(1/M(Mg)-1/M(Zn))=m(H₂)/{M(H₂)m}-1/M(Zn)

w=[m(H₂)/{M(H₂)m}-1/M(Zn)]/(1/M(Mg)-1/M(Zn))

w=0.583 (58.3%)

5 0

3 years ago

WILL GIVE BRAINLIEST

OverLord2011 [107]

Answer:

butylphenyl ether.

Explanation:

The formula of the compound is:

CH₃ - CH₂ - CH₂ - CH₂ - O - C₆H₅

1. The functional group is of the kind R - O - R', i.e. two alkyl groups each attached to one end of the oxygen atom. That means that the compound is an ether.

2. One group attached to the oxygen group is CH₃ - CH₂ - CH₂ - CH₂ - which has 4 carbons and is named butyl group.

3. The other group attached to the oxygen atom is C₆H₅ - which is derived from ciclohexane as is known as phenyl group.

4. Using the rule of naming the subtituents in alphabetical order, you name butyl first and phenyl second, so it is butylphenyl ether.

4 0

3 years ago

It isn't possible to transfer heat from an object at a lower temperature to another object at a _ temperature unless work is don

lisov135 [29]

Higher. Because this type of heat transfer is conduction, meaning that heat always transfers to cooler objects.

5 0

3 years ago

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