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3 years ago

Hey I need help with 84-88

Chemistry

1 answer:

mylen [45]3 years ago

6 0

Answer:

84. 3

85. 6

86. 3

87. 6

Explanation:

84. 3

85. 6

86. 3

87. 6

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(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of

gregori [183]

Detonation of nitroglycerin:

$4C_3H_5N_3O_9 ------\ \textgreater \ 12CO_2+6N_2+O_2+H_2O$

<span>Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g
</span>
Moles = mass / molar mass = 3.184<span> g/ 227.0872 g/mol = 0.01402
</span>
the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841

<span>the ratio between nitroglycerin and O2 is 4 : 1 </span>
moles O2 = 0.01402 x 1 / 4 = 0.0035

<span>the ratio between nitroglycerin and water is 4 : 1 </span>
<span>in the same way moles water = 0.005258 </span>

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758<span> x 55 = 5.78 L </span>

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g

6 0

3 years ago

When ammonium phosphate and nickel(ii) nitrate solutions are mixed, what precipitates out?

Sphinxa [80]

2(NH4)3PO4 (aq) + 3Ni(NO3)2(aq) ------> Ni3(PO4)2(s) + 6NH4NO3 (aq)

Ni3(PO4)2 is a precipitate.

5 0

3 years ago

Read 2 more answers

How many oxygen molecules are needed to make 10 carbon dioxide molecules according to the following balanced chemical equation?

11Alexandr11 [23.1K]

<h2 /><h2 /><h2>answer.</h2>

five oxygen molecules

step by step explanation.

according to the equation,one molecule of oxygen is enough to react with two carbon molecules thus 10 carbon molecules need 5oxygen molecules

6 0

3 years ago

What is the percent composition HCN?

kupik [55]

Answer:

see calculations in explanation

Explanation:

percent = part/total x 100%

part = ∑ atomic mass of element

hydrogen = 1.008 amu (atomic mass units)
carbon = 12.011 amu
nitrogen = 14.007 amu

total = ∑ molecular mass of compound

= H amu + C amu + Namu

= 1.008 amu + 12.011 amu + 14.007 amu

= 27.026 amu

%H = (1.008amu/27.026amu)100% = 3.730%

%C = (12.011amu/27.026amu)100% = 44.442%

%N = (14.007amu/27.026amu)100% = 51.827%

Check results ∑%values = 100%

3.730% + 44.442% + 51.827% = 99.999% ≅ 100%

7 0

3 years ago

Use the molar solubility 3.27×10−11m in pure water to calculate ksp for nis.

Ne4ueva [31]

Answer:

Ksp = 1.07x10⁻²¹

Explanation:

Molar solubility is defined as moles of solute can be dissolved in 1L.

Ksp for NiS is defined as:

NiS(s) ⇄ Ni²⁺(aq) + S²⁻(aq)

Ksp = [Ni²⁺] [S²⁻]

As molar solubility is 3.27x10⁻¹¹M, concentration of [Ni²⁺] and [S²⁻] is 3.27x10⁻¹¹M for both.

Replacing:

Ksp = [3.27x10⁻¹¹M] [3.27x10⁻¹¹M]

4 0

2 years ago