Answer:
Zn+H2O ------ ZnO + H2 is the correct answer
Answer:
what do u mean????? i dont get the question
The question is incomplete. Complete question is attached below:
...........................................................................................................................
Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
(True) <span>Organisms belonging to the same species can mate and produce fertile offspring</span>
Answer:
2.34 molality
Explanation:
Mole weight of KOH ( using periodic table ...rounded to 3 s.f.) =
56.1 gm/mole
Number of moles in 43.2 g
43.2 g / 56.1 gm / mole =.770 mole
molality = .770 mole / .329 kg = 2.34 m