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lawyer [7]
3 years ago
8

Compared to a 1.0-liter aqueous solution with a pH of 7.0, a 1.0-liter aqueous solution with a pH of 5.0 contains

Chemistry
2 answers:
Olin [163]3 years ago
7 0

Answer:

Its Actually 100 More Hydromium ions

Explanation:

grin007 [14]3 years ago
5 0

Answer:

2. 100 times more hydroxide ions,

Explanation:

Acidity and alkalinity are measured with a logarithmic scale called pH. Each one-unit change in the pH scale corresponds to a ten-fold change in hydrogen ion concentration. Therefore, a 1.0 liter aqueous solution with a pH of 5.0 contains 100 times more hydronium ions than a 1.0 liter aqueous solution with a pH of 7.0

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What volume of 0.200 M H2SO* will be needed to neutralize<br><br> 50.00 mL of 0.178 MNaOH?
mixas84 [53]

Answer:

10.00 mL

Explanation:

Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0
4 years ago
PLS HELP ME I HAVE TILL 12
MariettaO [177]

Answer:

alright bud lets see hmm.... the answer is a. 90.5kpa

Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

3 0
3 years ago
"Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 89), leucine (131), tryptophan
Cloud [144]

Answer:

- Alanine =  5.61 mmoles

- Leucine = 3.81 mmoles

- Tryptophan = 2.45 mmoles

- Cysteine = 4.13 mmoles

- Glutamic acid = 3.40 mmoles

Explanation:

Mass / Molar mass = Moles

Milimoles = Mol . 1000

500 mg / 1000 = 0.5 g

- Alanine = 0.5 g / 89 g/m → 5.61x10⁻³ moles  . 1000 = 5.61mmoles

- Leucine = 0.5 g / 131 g/m → 3.81 x10⁻³ moles  . 1000 = 3.81 mmoles

- Tryptophan = 0.5 g / 204 g/m →  2.45x10⁻³ moles . 1000 = 2.45 mmoles

- Cysteine = 0.5 g / 121 g/m → 4.13x10⁻³ moles . 1000 = 4.13 mmoles

- Glutamic acid = 0.5 g 147 g/m → 3.40x10⁻³ moles . 1000 =  3.4 mmoles

5 0
3 years ago
How many grams of oxygen gas (02) are needed to completely react with 9.30 moles
Luba_88 [7]

Answer:

223 g O₂

Explanation:

To find the mass of oxygen gas needed, you need to (1) convert moles Al to moles O₂ (via the mole-to-mole ratio from reaction coefficients) and then (2) convert moles O₂ to grams O₂ (via the molar mass). When writing your ratios/conversions, the desired unit should be in the numerator in order to allow for the cancellation of the previous unit. The final answer should have 3 sig figs because the given value (9.30 moles) has 3 sig figs.

4 Al + 3 O₂ ----> 2 Al₂O₃
^         ^

Molar Mass (O₂): 32.0 g/mol

9.3 moles Al          3 moles O₂              32.0 g
-------------------  x  ---------------------  x  --------------------  =  223 g O₂
                              4 moles Al               1 mole

6 0
2 years ago
From this list, select the element that forms π bonds most readily. from this list, select the element that forms bonds most rea
Finger [1]

Nonmetals which are located in the second row form pi bonds more easily than the elements situated in the third row and below. Actually there are no compounds or molecules known that forms covalent bonds to the noble gas Ne and Ar. Hence the other second row element which is Carbon, is the element that forms pi bonds most readily.

 

Answer:

<span>C</span>

3 0
3 years ago
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