What is a mol in chemistry

Which of the following is TRUE? A) The equivalence point is where the amount of acid equals the amount of base during any acid-b

liberstina [14]

Answer:

the correct option is B

Explanation:

The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .

5 0

3 years ago

Read 2 more answers

While you were "sweating" your chemistry test, water vapor evaporates from your body, absorbing 50,000 J of energy. (assume no

TiliK225 [7]

Answer:

$\boxed {\boxed {\sf B. \ 22 \ grams}}$

Explanation:

We need to use the formula for heat of vaporization.

$Q=H_{vap}*m$

Identify the variables.

The heat absorbed by the evaporating water is the <u>latent heat of vaporization. </u>For water, that is 2260 Joules per gram.

Q is the energy, in this problem, 50,000 Joules.

m is the mass, which is unknown.

$H_{vap}=2260 \ J/g\\Q=50,000 \ J \\$

Substitute the values into the formula.

$50,000 \ J=2260 \ J/g*m$

We want to find the mass. We must isolate the variable, m.

m is being multiplied by 2260 J/g. The inverse operation of multiplication is division. Divide both sides by 2260 J/g.

$\frac{50,000 \ J}{2260 \ J/g} =\frac{2260 \ J/g*m}{2260 \ J/g}$

$\frac{50,000 \ J}{2260 \ J/g} =m$

Divide. Note that the Joules (J) will cancel each other out.

$\frac{50,000 \ }{2260 \ g} =m$

$22.1238938 \ g =m$

Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.

$22 \ g \approx m$

The mass is about 22 grams, so choice B is correct.

3 0

3 years ago

Help me plz, I need help on this.

kirza4 [7]

Omg i lost everything ugh
To do it again

1. 12g+2(16g)= 44g/mol
25.01/ 44g/mol= .... mol

2. 14g+3(1g)= 17g/mol
34.05g/ 17g/mol=.... mol

3. 23g+1g+ 12g+ 3(16g)= 84g/mol
17.31g/ 84g/mol=.... mol

4. 6(12g)+12(1g)+6(16g)= 180g/mol
123.44g/ 180g/mol=.... mol

5. 23g+16g+1g= 40g/mol
2.2mol x 40g/mol= .... g

6. 2(35g)= 71g/mol
4.5mol x 71g/mol= .... g

7. 137g+ 2(14g)+ 6(16g)= 261g/mol
0.002mol x 261g/mol= ....g

8. 2(56g)+ 3(32g)+ 12(16g)= 400g/mol
5.4mol x 400g/mol=.... g

I cant believe i had to do this all over

4 0

3 years ago

A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas

Svetradugi [14.3K]

According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
$\frac{P1V1}{P2V2} = \frac{T1}{T2}$

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = $\frac{P1V1T2}{T1} = \frac{100 X 2 X 400}{200X100}$
∴ V2 = 4 m3

7 0

3 years ago

Name the seventh inner transition metal in period 6

vladimir1956 [14]

Answer:

follow me and mark me brainliest

8 0

4 years ago