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3 years ago

How do catalysts affect energy of reactions

Chemistry

2 answers:

Strike441 [17]3 years ago

5 0

Explanation:

A catalyst lowers the activation energy of a reaction allowing them to proceed faster than they would naturally. Activation energy is the free energy that is required to be input in the reactant side to activate them to the transition state after which the reaction proceeds spontaneously to products.

An example of a catalyst is platinum, that is put in the exhaust of cars, to help convert carbon monoxide to carbon dioxide before it is emitted into the air.

natima [27]3 years ago

3 0

Answer: they lower these activation required for the reactions to take place.

Explanation:

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Answer:

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2 years ago

Type of molecule is shown below?<br> H<br> O=C<br> H

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Answer:

Carbonyl

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While the diagram is slightly unclear, the molecule most likely being shown is a carbonyl. A molecule is a carbonyl when there is a carbon double-bonded to an oxygen.

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1 year ago

The number of molecules in 7g nitrogen

charle [14.2K]

Answer:

the number of molecules in 7g nitrogen

Ans) 7 gram of Nitrogen contains 1.5×10^23 molecules =1.5e+23

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2 years ago

What is the approximate time of death if the body temperature was 15.6°C?

WARRIOR [948]

Answer:

This stiffening process, called Rigor Mortis, has a roughly known time of occurrence and can therefore be used to estimate time of death. In general: If the body feels warm and no rigor is present, death occurred under 3 hours before. If the body feels warm and stiff, death occurred 3-8 hours earlier.

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2 years ago

635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?

Sveta_85 [38]

The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

So, pressure∝ $\frac{1}{volume}$

Thus, if two pressure and two volumes are given then,

$P_{1} V_{1} = P_{2} V_{2}\\$

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

$8*635*10^{-3} = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} = 5.08 L$

Thus, the new volume at standard temperature and pressure is 5.08 L.

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2 years ago