Answer:
4.87g
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of solution = 0.35kg
Molality = 0.238 m
Mass of NaCl =..?
Step 2:
Determination of the number of mole of NaCl in the solution.
Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:
Molality = mol of solute /mass of solvent (kg)
With the above formula, we calculate the mole of NaCl present in the solution as follow:
Molality = mol of solute /mass of solvent (kg)
0.238 = mol of NaCl /0.35
Cross multiply
mol of NaCl = 0.238 x 0.35
mol of NaCl = 0.0833 mol
Step 3:
Determination of the mass of NaCl in 0.0833 mol of NaCl.
This is illustrated below:
Number of mole NaCl = 0.0833 mol
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl =..?
Mass = number of mole x molar Mass
Mass of NaCl = 0.0833 x 58.5
Mass of NaCl = 4.87g
Therefore, 4.87g of NaCl is contained in the solution.
<u>First part:</u>
2 atoms of Na
6 atoms of N
<u>Second part:</u>
2 atoms of N
2 atoms of Na
Why?
We are given the chemical reaction, so, we can extract the number of atoms for both reactants and products.
We are given the chemical equation:
We can rewrite it as follow:
From the reactants, we have:
From the products we have:
Hence, we have that:
There are <u>6 atoms of N in the reactants</u> and <u>6 atoms of N in the products.</u>
and
There are <u>2 atoms of Na in the reactants</u> and<u> </u><u>2 atoms of Na in the products</u> since we have a balanced equation.
Have a nice day!
Ping pong ball - 0.0840 g
Bottle cap - 0.92 g
Marble - 2.711 g
The answer:
La planta tiene las hojas secas.
