<u>Answer:</u> The temperature of the ideal gas is 
<u>Explanation:</u>
To calculate the temperature, we use the equation given by ideal gas equation:

where,
P = Pressure of the gas = 142,868 Pa = 142.868 kPa (Conversion factor: 1 kPa = 1000 Pa)
V = Volume of gas = 1.0000 L
n = number of moles of ideal gas = 0.0625 moles
R = Gas constant = 
T = temperature of the gas = ?
Putting values in above equation, we get:

Hence, the temperature of the ideal gas is 
The rate constant is mathematically given as
K2=2.67sec^{-1}
<h3>What is the Arrhenius equation?</h3>
The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

Therefore
KT1= 0.0110^{-1}
T1= 21+273.15
T1= 294.15K
T2= 200
T2=200+273.15
T2= 473.15K
Ea= 35.5 Kj/Mol
Hence, in j/mol R Ea is
Ea=35.5*1000 j/mol R

K2/0.0110 =e^(5.492)
K2/0.0110 =242.74
K2= 242.74*0.0110
K2=2.67sec^{-1}
In conclusion, rate constant
K2=2.67sec^{-1}
Read more about rate constant
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Answer:
1.
Explanation:
1. They are made up of two or more Pure substances that are not chemically bonded together and appear non-uniform
A heterogeneous mixture is not chemically combined and its components are visible and can be seen.
Answer:

Explanation:
= Concentration of stock solution
= Concentration of solution
= Volume of stock solution = 19 mL
= Volume of solution = 0.31 L= 310 mL
We have the relation


The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.
Answer:10^27 atoms in an apple
Explanation: