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tatyana61 [14]
3 years ago
13

Who proved that there are charged particles in an atom? dalton chadwick thomson bohr or rutherford?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
5 0
Dalton Chadwick Thomson Bohr invented this theory.
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If a compound begins with a metal, it most likely is a _______ compound
Bess [88]

Answer:

Metallic compound

Explanation:

Metallic compound -

A metallic compound refers to the species having at least one metal, is known  as a metallic compound.

In general a metallic compound consists of two ions, a positive ion or the cation, is is basically a metal, and,

a negative ion or an anion, which is a non - metal.

Hence, from the given statement of the question,

The correct answer is - metallic compound.  

8 0
3 years ago
Arrange the compounds by their reactivity toward electrophilic aromatic substitution.
swat32

Answer:

The order of reactivity towards electrophilic susbtitution is shown below:

a. anisole > ethylbenzene>benzene>chlorobenzene>nitrobenzene

b. p-cresol>p-xylene>toluene>benzene

c.Phenol>propylbenzene>benzene>benzoic acid

d.p-chloromethylbenzene>p-methylnitrobenzene> 2-chloro-1-methyl-4-nitrobenzene> 1-methyl-2,4-dinitrobenzene

Explanation:

Electron donating groups favor the electrophilic substitution reactions at ortho and para positions of the benzene ring.

For example: -OH, -OCH3, -NH2, Alkyl groups favor electrophilic aromatic substitution in benzene.

The -I (negative inductive effect) groups, electron-withdrawing groups deactivate the benzene ring towards electrophilic aromatic substitution.

Examples: -NO2, -SO3H, halide groups, Carboxylic acid groups, carbonyl gropus.

4 0
3 years ago
Which is the smallest particle into which a compound can be broken down and still remain the same compound? A. atom B. mixture C
Andre45 [30]
The smallest would be a compound
4 0
3 years ago
Whats the answer?? Please help
Katarina [22]

Answer:

.

Explanation:

4 0
3 years ago
How many moles of solute are in 53.1 mL of 12.5M HCI?
Deffense [45]
Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).
6 0
2 years ago
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