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3 years ago

Select all the correct images.Select the two atomic models that belong to the same element.

Chemistry

2 answers:

posledela3 years ago

6 0

Answer:

the one in the top right corner and the one in the bottom left corner

Explanation:

nasty-shy [4]3 years ago

6 0

Answer : The atomic models that belongs to the same element are atomic model 2 and 3. (Shown below)

Explanation :

As we know that an atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or center of the nucleus where the mass of the an atom is concentrated and the electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

Atomic number is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Same element has same number of protons.

Atomic model 1 : In this model, there are 8 number of electrons, 8 number of protons and 8 number of neutrons.

Atomic model 2 : In this model, there are 5 number of electrons, 5 number of protons and 6 number of neutrons.

Atomic model 3 : In this model, there are 5 number of electrons, 5 number of protons and 5 number of neutrons.

Atomic model 4 : In this model, there are 6 number of electrons, 6 number of protons and 6 number of neutrons.

From this we conclude that, the atomic model 2 and 3 has same number of protons. So, these two models belongs to the same element.

Hence, the atomic models that belongs to the same element are atomic model 2 and 3. (Shown below)

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What is the difference between atoms and molecules?

Vera_Pavlovna [14]

The correct answer is:

~Difference between atoms and molecules is that when similar atoms combine together in varying numbers, molecules of different properties can be formed.

Hope this helps!!!

7 0

4 years ago

Question 22 A VHF television station assigned to channel transmits its signal using radio waves with a frequency of . Calculate

aleksklad [387]

The question is incomplete, here is the complete question:

A VHF television station assigned to channel transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate the wavelength of the radio waves. Round your answer to 3 significant digits.

Answer: The wavelength of the radio waves is 4.54 m

<u>Explanation:</u>

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light

c = speed of light = $3\times 10^8m/s$

$\nu$ = frequency of light = $66.0MHz=66.0\times 10^6s^{-1}$

Putting the values in above equation, we get:

$\lambda=\frac{3\times 10^8m/s}{66.0\times 10^{6}s^{-1}}=4.54m$

Hence, the wavelength of the radio waves is 4.54 m

6 0

4 years ago

Suppose 20.23 g of glucose are dissolved in 95.75 g of water at 27.0 OC. Glucose is nonvolatile (has no vapor pressure) and has

leonid [27]

Answer:

Explanation:

From the information given :

we can understand the solute is glucose and the solvent is water,

So, the weight of glucose = 20.23 g

the molecular weight of glucose = 180.2 g/mol

weight of water = 95. 75 g

the molecular weight of water = 18.02 g/mol

pure vapor pressure of water $P_A = 26.7 \ mmHg$ at 27°C

moles of glucose = weight of glucose/ molecular weight of glucose

= 20.23/180.2

= 0.11 mole

moles of water = weight of water / molecular weight of water

= 95.75/18.02

= 5.31 mole

mole fraction of glucose $X_{glucose} =$ (moles of glucose)/(moles of glucose+ moles of water)

$X_{glucose} =$ 0.11/(0.11 + 5.31)

$X_{glucose} =$ 0.0203

mole fraction of glucose $X_{water} =$ (moles of water)/(moles of water+ moles of glucose)

$X_{water} =$ 5.31/ (5.31 + 0.11)

$X_{water} =$ 0.9797

Using Raoult's Law:

$P_S = P^0_A \times X_A \ \ \ OR \ \ \ P_A = P^0_A \times X_A$

where:

$P_S$ = vapor pressure of the solution

$P_A$ = total vapor pressure of the solution

$P^0_A$ = vapor pressure of the solvent in the pure state

$X_A$ = mole fraction of solvent i.e. water

$P_A =$ 95.75 × 0.9797

$P_A =$ 93.81 mmHg

the total vapor pressure of the solution = 93.81 mmHg

4 0

3 years ago

GIVING BRAINLIEST 5 STARS AND HEART!

andrew11 [14]

Generally speaking, acidic soil, with a pH lower than 6.0, yields blue or lavender-blue hydrangea blooms. Alkaline soil, with a pH above 7.0, promotes pinks and reds. With a pH between 6 and 7, the blooms turn purple or bluish-pink. To lower your pH, add garden sulfur or aluminum sulfate to your soil.

The secret's in the soil

Let’s look at why pH is so important.

Most major plant nutrients are more accessible at a pH of 6 to 6.5. A pH that is too high or too low can keep plants from absorbing nutrients from the soil. The nutrients are unavailable — or not absorbable — to the plant because of soil's chemistry. This problem can manifest itself in a variety of ways, but in the case of hydrangeas, the bloom color changes.

Color variation in hydrangeas is due to the presence or absence of aluminum compounds in the flowers. If aluminum is present, the color is blue. If it is present in small quantities, the color is variable between pink and blue. If aluminum is absent, the flowers are pink.

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3 years ago

Read 2 more answers

How many molecules of sugar are there in 1 can of soda?

Korvikt [17]

Answer:

$5.8\cdot 10^{22}$

Explanation:

Since no information was provided about the can of soda, let's take an example of 1 can of 12 fl oz (368 g) Coca-Cola.

The nutrition facts state that it contains 33 g of sugar. In order to calculate the number of molecules, we firstly need to know the molecular formula of sugar. Sugar can be represented by $C_{12}H_{22}O_{11}$ .

Our first step is to find the molar mass of sugar:

$M_{C_{12}H_{22}O_{11}} = 342.3 g/mol$

Secondly, dividing mass of sugar, $m = 33 g$ , by the molar mass will yield the number of moles of sugar:

$n_{C_{12}H_{22}O_{11}}=\frac{m}{M}$

Finally, multiplying moles by the Avogadro's constant will yield the number of molecules:

$N_{C_{12}H_{22}O_{11}}=n_{C_{12}H_{22}O_{11}}\cdot N_A =\frac{m}{M} \cdot N_A = \frac{33 g}{342.3 g/mol} \cdot 6.022 \cdot 10^{23} mol^{-1} = 5.8\cdot 10^{22}$

8 0

4 years ago