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dlinn [17]
2 years ago
12

100 Points

Mathematics
2 answers:
Strike441 [17]2 years ago
8 0

Answer:

1) Consistent Independent

2) Coincident

3) Inconsistent

Step-by-step explanation:

atroni [7]2 years ago
7 0

\left\{\begin{array}{ccc}ax+by=c\\ax+by=c\end{array}\right\Rightarrow\text{coincident}\\\\\left\{\begin{array}{ccc}ax+by=c\\ax+by=d\\c\neq d\end{array}\right\Rightarrow\text{inconsistent}\\\\\left\{\begin{array}{ccc}ax+by=c\\dx+ey=c\\a\neq d\ or\ b\neq e\end{array}\right\Rightarrow\text{consistent independent}

\left\{\begin{array}{ccc}x+5y=-2\\x+5y=4\end{array}\right\Rightarrow\boxed{\text{inconsistent}}\\--------------------------------\\\left\{\begin{array}{ccc}y=3x+4&\text{subtract 3x from both sides}\\-2x+y=4\end{array}\right\\\\\left\{\begin{array}{ccc}-3x+y=4\\-2x+y=4\end{array}\right\Rightarrow\boxed{\text{consistent independent}}\\-----------------------------\\\left\{\begin{array}{ccc}3x+y=4\\-6x-2y=-8&\text{divide both sides by (-2)}\end{array}\right\\

\left\{\begin{array}{ccc}3x+y=4\\3x+y=4\end{array}\right\Rightarrow\boxed{\text{coincident}}

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Answer:

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Step-by-step explanation:

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Answer:

The pair of equations which has (2,12) as its solution is,

equation B and equation C.

                           

Step-by-step explanation:

According to the question,

equation of line A is \frac {y - 16}{x + 6} = \frac {16 + 4}{-6 - 9}

                            or, \frac {y - 16}{x + 6} = \frac {-4}{3}

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                            or, 3y + 4x = 24 ------------------(1)

Now, the point (2, 12) doesn't satisfy (1). Hence, (2,12) is not a solution for the line A.

Equation of line B is, \frac {y - 20}{x + 2} = \frac {20 - 0}{-2 - 8}

                              or, \frac {y - 20}{x + 2} = -2

                              or, y - 20 = -2x  - 4

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The point (2,12) is satisfied by (2). Hence, (2, 12) is a solution for line B.

Equation of line C is, \frac {y + 6}{x + 7} = \frac {20 + 6}{6 + 7}

                              or, \frac {y + 6}{x + 7} = 2

                              or, y + 6 = 2x + 14

                              or. y - 2x = 8 -----------------------------------(3)

The point (2, 12) is satisfied by (3). Hence, (2 , 12) is a solution for the line C.

Equation of line D is, \frac {y - 20}{x - 7} =\frac {20 + 7}{7 - 0}

                               or, \frac {y - 20}{x - 7} = \frac {27}{7}

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The point (2, 12) is not satisfied by (4). hence, (2, 12) is not a solution of the line D

Hence, the pair of equations which has (2,12) as its solution is,

equation B and equation C.

                           

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