Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
sorry I forgot try googling it
Answer:
$4250
Step-by-step explanation:
i = prt
or
p = i / rt
where,
i = $1,785
r = 6% = 0.06
t = 7 years
So, we can calculate initial vale by putting the values in above equation;
p = $1,785 / (0.06 x 7)
p = $1,785 / 0.42
p = $4,250
Hence the initial value will be $4250
Answer:
y = -4/3x - 3
Step-by-step explanation:
