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Vsevolod [243]
4 years ago
5

Students design a model roller-coaster track. They place a rubber ball at the highest point on the track and let it go. The ball

rolls along the track pulled only by the force of gravity. Eventually, it comes to a stop. Which change to the design will result in the ball moving the greatest distance?
Physics
2 answers:
Zanzabum4 years ago
4 0

Answer:

Raising the highest point of the track to a higher point

Explanation:

When the rubber ball starts its motion, from the highest point of the track, it has only gravitational potential energy, given by:

U=mgh

where m is the mass of the ball, g is the gravitational acceleration and h is the height above the ground.

As the ball descends the track, this potential energy is partially converted into kinetic energy, given by:

K=\frac{1}{2}mv^2

(where m is the mass and v is the speed)

and partially lost as heat, due to the friction between the surface of the track.

As a consequence, the higher the initial height of the track (h in the formula), the greater will be the kinetic energy gained by the ball. A greater kinetic energy means a larger velocity, which also means that the ball will cover a longer distance before stopping.

riadik2000 [5.3K]4 years ago
3 0

Answer:

<h2>B) Using a metal ball instead of a rubber ball</h2>

Students design a model roller-coaster track. They place a rubber ball at the highest point on the track and let it go. The ball rolls along the track pulled only by the force of gravity. Eventually, it comes to a stop.

 

 Which change to the design will result in the ball moving the greatest distance?

A) Moving the track to a higher location  

B) Using a metal ball instead of a rubber ball  

C) Covering the track with a strip of sandpaper  

D) Decreasing the height at which the ball is let go

Explanation:

The ball eventually stops moving because it loses energy to the track and surrounding air. This energy is lost as heat, which is produced by friction between the ball and the track. Using a metal ball instead of a rubber ball will reduce friction, making the model coaster more efficient because less energy is lost to the environment.

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Mariulka [41]

Answer:

A. 1222,10 N

Explanation:

First, we determine the value of the acceleration that the hydraulic launching system must guarantee. Let’s remember that the definition of acceleration is the rate of change of velocity with respect to time. Therefore:

a_hyd = ∆v/∆t = (54 m/s-0)/(3,8 s-0) = 14,21 m/s^2  

According to Newton’s second law:

∑F_net = m*a = 86 kg*14,21 m/s^2 = 1222,10 N

So, the net force required to accelerate an 86-kg man is 1222,10 N

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3 0
4 years ago
A 12.0-kilogram object is lifted from the ground to a height of 4.00 meters.
kow [346]

Answer:

3 j

Explanation:

12.0 kilo / 4.00 meters = 3 j

4 0
3 years ago
A 8.0×104kgspaceship is at rest in deep space. Its thrusters provide a force of 1200kN. The spaceship fires its thrusters for 20
Sladkaya [172]

Answer:

Time = 40 s

It will take the spaceship 40s to coast that distance.

Explanation:

Using the impulse momentum equation;

Impulse = change in momentum

Ft = m(∆v) ........1

Given;

Force F = 1200kN

time of action t = 20s

Mass of spaceship m = 8.0×10^4 kg

∆v = change in velocity

Substituting the values into equation 1;

1200kN × 20s =8.0×10^4 kg × ∆v

∆v = 1200000×20/80000

∆v = 300 m/s

Since it was initially at rest, V0 = 0

Final velocity V2 = 300 + 0

V2 = 300m/s

Time To travel 12 km,

Time = distance/speed

Distance = 12 km = 12000m

Speed = 300m/s

Time = 12000/300

Time = 40 s

It will take the spaceship 40s to coast that distance.

4 0
3 years ago
A mole of an ideal gas expands from a initial volume of 7 l to 15 l at a constant temperature of 340 k. how much work is done by
Sindrei [870]
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3 0
4 years ago
A point charge A of charge +4micro coloumb and another B of -1 micro coloumb are placed at a distance in air 1m apart then the d
andrew11 [14]

Answer:

Explanation:

Given that,

A point charge is placed between two charges

Q1 = 4 μC

Q2 = -1 μC

Distance between the two charges is 1m

We want to find the point when the electric field will be zero.

Electric field can be calculated using

E = kQ/r²

Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.

Then, the magnitude of the electric at point x is zero.

E = kQ1 / r² + kQ2 / r²

0 = kQ1 / x²  - kQ2 / (1-x)²

kQ1 / x² = kQ2 / (1-x)²

Divide through by k

Q1 / x² = Q2 / (1-x)²

4μ / x² = 1μ / (1 - x)²

Divide through by μ

4 / x² = 1 / (1-x)²

Cross multiply

4(1-x)² = x²

4(1-2x+x²) = x²

4 - 8x + 4x² = x²

4x² - 8x + 4 - x² = 0

3x² - 8x + 4 = 0

Check attachment for solution of quadratic equation

We found that,

x = 2m or x = ⅔m

So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.

5 0
3 years ago
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