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4 years ago

11

A leaf falls through the air, floating as it falls. Air resistance is visibly affecting the leaf. Which two properties of the le

af are allowing it to be affected by air resistance

2 answers:

Black_prince [1.1K]4 years ago

5 0

Air resistance is able to get ahold of the leaf because of
the leaf's small weight and large surface area.

Norma-Jean [14]4 years ago

4 0

A) acceleration due to gravity & D) surface area

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4 years ago

What is the most likely outcome of increasing the number of slits per unit distance on a diffraction grating?1) lines become nar

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2 years ago

(a) Suppose that a NASCAR race car is moving to the right with a constant velocity of +82 m/s. What is the average acceleration

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4 years ago

Two 2.00 cm * 2.00 cm plates that form a parallel-plate capacitor are charged to { 0.708 nC. What are the electric field strengt

lisov135 [29]

Answer:

(a) $E=200000Volts/meter$

(b) $E=200000Volts/meter$

Explanation:

Given data

Area A=4.0 cm²=0.0004 m²

Electric permittivity ε=8.854×10⁻¹² farads/meter

Charge q=0.708 nC

To find

(a) Potential at distance=1.00mm

(b) Potential at distance=2.00mm

Solution

For (a) Potential at distance=1.00mm

First we need to find the capacitance

So

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/1.00*10^{-3} )\\ C=3.5416*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/3.5416*10^{-12}farads\\V=200Volts$

So Electric potential is given as:

$E=V/d\\E=(200V)/(1*10^{-3}m )\\E=200000Volts/meter$

For (b) Potential at distance=2.00mm

First we need to find the capacitance

So

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/2.00*10^{-3} )\\ C=1.7708*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/1.7708*10^{-12}farads\\V=400Volts$

So Electric potential is given as:

$E=V/d\\E=(400V)/(2.0*10^{-3}m )\\E=200000Volts/meter$

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4 years ago

What type of particle found inside the atom is uncharged

soldi70 [24.7K]

The neutron is uncharged. That's why it was
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3 years ago

Read 2 more answers