All categories

3 years ago

If your doctor wanted to see how a specific organ was functioning, they would order a

2 answers:

6 0

Depending on which organ and how it's SUPPOSED to function, the best choice might be a CAT scan, but more likely an MRI or Ultrasound.

dem82 [27]3 years ago

4 0

They have to order a CAT scan

You might be interested in

Quick please and will give Brainliest!!!

masha68 [24]

25 nC

That is the answer

3 0

3 years ago

Read 2 more answers

A sound wave travels through water at 1,500 m/s. How far would it travel in 5 s?

hichkok12 [17]

7500m because 1,500 in 1 sec so 1500x5 7500

8 0

3 years ago

Read 2 more answers

One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit

nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

$\lambda$ = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

$\theta=\dfrac{1.22\lambda}{D}$

The width is given by

$d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m$

The required width is 0.000003782 m

Minimum resolvable line separation is given by

$\dfrac{0.000003782}{2}=0.000001891\ m$

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when $\lambda=157\ nm$

$d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m$

The new minimum resolvable line separation between adjacent lines is

$\dfrac{0.00000239425}{2}=0.000001197125\ m$

6 0

4 years ago

A circular loop carrying a current of 1.6 A is oriented in a magnetic field of 0.30 T. The loop has an area of 0.14 m 2 and is m

konstantin123 [22]

Answer:

The torque on the loop is $2.4 \times 10^{-2}$ Nm

Explanation:

Given:

Current $I = 1.6$ A

Magnetic field $B = 0.30$ T

Area of loop $A = 0.14$ $m^{2}$

Angle between magnetic field and area vector $\theta =$ 21°

Form the formula of torque in case of magnetic field,

г $= MB \sin \theta$

Where $M =$ magnetic moment

$M = IA$

г $= IAB \sin 21$

г $= 1.6 \times 0.30 \times 0.14 \times 0.3583$

г $=2.4 \times 10^{-2}$ Nm

Therefore, the torque on the loop is $2.4 \times 10^{-2}$ Nm

7 0

4 years ago

25. You are asked to find the area of a room that is 4.56 m long and 5.668 m wide. How many significant

just olya [345]

Answer:

Option B

Explanation:

The two dimensions have the following significant numbers

4.56- 3 significant numbers

5.668- 4 significant figures

When responding, we give area as per the most precise number given hence the smallest (most precise) significant figures in these two numbers is 3. Therefore, the area will be given to 3 significant figures ie

4.56*5.668=25.84608 square meters

Area=25.8 square meters

4 0

3 years ago