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Tju [1.3M]
3 years ago
13

Famous comparative and superlative form​

Physics
2 answers:
inn [45]3 years ago
4 0

\huge{\fbox{\red{Answer:}}}

<h3>Word Given : </h3>

Famous

___________________✍

Comparative Form : more famous

Superlative Form : most famous

Hope you understand❣

Helga [31]3 years ago
3 0

Answer:

comparative----more famous, superlative----- most famous

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What happens to the gravitational force between two objects if:
tiny-mole [99]

Answer:

See the answers below

Explanation:

This problem and its respective questions can be easily solved using Newton's law of universal gravitation. Which can be calculated by means of the following expression.

F =G*\frac{m_{1}*m_{2}}{r^{2} }

where:

G = it is the universal gravitation constant. = 6.673 x 10⁻¹¹ [N*m²/kg²]

m1 = mass of the first body [kg]

m2 = mass of the second body [kg]

r = distance among the bodies [m]

a. the mass of one is doubled?

When this happens we see that the force is increased twice as well, since the mass is in the numerator of the expression.

b. The masses of both are doubled?

If both masses are doubled the force is increased to four times its original value since the terms of the masses are in the numerator of the expression.

c. The distance between them is doubled?

In this case the force is decreased to half of its original value, since the distance is in the denominator of the expression of universal gravitation.

5 0
3 years ago
A hollow cylinder of mass 2.00 kgkg, inner radius 0.100 mm, and outer radius 0.200 mm is free to rotate without friction around
kipiarov [429]

Answer: 2.86 m

Explanation:

To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,

ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)

In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have

mgh + 0 = 0 + KE(f)

To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have

mgh = 1/2mv² + 1/2Iw²

To get the inertia of the bodies, we use the formula

I = [m(R1² + R2²) / 2]

I = [2(0.2² + 0.1²) / 2]

I = 0.04 + 0.01

I = 0.05 kgm²

Also, the angular velocity is given by

w = v / R2

w = 4 / (1/5)

w = 20 rad/s

If we then substitute these values in the equation we have,

0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)

4.9h = 4 + 10

4.9h = 14

h = 14 / 4.9

h = 2.86 m

8 0
3 years ago
Read 2 more answers
1.
MAXImum [283]

Answer:

true

Explanation:

Newton is the measure of the force with turns to be gravity multiplying the mass. Thus, the forces acts on the particles in the direction of the movement of the particles

7 0
3 years ago
What is the name of the phenomenon that causes observed light from a star to change its wavelength?
blagie [28]

Answer: This is called the Doppler effect, where waves shift frequency and wavelength as the source travels towards you (higher frequency, shorter wavelength) or away from you (lower frequency, longer wavelength)

Explanation:

hoped this helped have a good day :)

5 0
3 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
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