An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A
few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.
x tan q
x sin q
x cos q
x tan q
x sin q
x cos q
2 answers:
Answer:
Tip of the rocket is x tan q meters above the ground.
Step-by-step explanation:
From the figure attached, at any moment after the launch of the rocket, tip of the rocket is at A.
AB is the height of the rocket tip from the ground and observer is x meters away from the launch pad.
Then tan q =
tan q =
AB = x tan q meters.
Tip of the rocket is x tan q meters above the ground.
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Step-by-step explanation:
1.) First, you need to take the whole numbers (9 and 1) and set them aside.
2.) Multiply the numerators from each fraction by one another. The numerators are the numbers on the top of the fraction. (Whatever you get on that will be the numerator of the answer!)
3.) Multiply the denominators by each other as well. The denominators are the numbers on the bottom. This will be the denominator of your answer.
4.) Now, you need to multiply your whole numbers (9 and 1) together.
5.) Then, simplify or reduce your answer. (this can't be simplified, as it is already in its simplest form)
Your answer will be 9 1/66.
Your work should look like this in the end:
