25% is the approximate production efficiency of this animal
Explanation:
Given ,
A ladybug eats 200 J of plant material
100 J is eliminated as feces
75 J are used in cellular respiration,
Now,
The approximate production efficiency of this animal :
200 - (100 +75) = 25 %
Answer:
As my study programme is concerned with the field of biotechnology, I hope that by the end of the proposed study programme, I will be able to gain knowledge about the molecular tools and the concepts and trends in genome editing. I shall be able to perform techniques such as PCR, gel electrophoresis, cell culturing easily. I would be able to grasp better knowledge in the fields of plant biotechnology, animal biotechnology, Industrial biotechnology and marine biotechnology.
Answer:
Temperature
Explanation:
catalyst have specify temperature range for their efficiency
Answer:
See the answer below
Explanation:
A DNase is also known as deoxyribonuclease and it is an enzyme that catalyzes the degradation of deoxyribonucleic acid by cleaving the phosphodiester linkage in their structures. Thus,<em> if the RNA is treated with a DNase before the plants are exposed to it, it will not make any difference. The plants will develop the same types of lesions as if they have been exposed to the mosaic virus.</em>
Unlike DNase, RNase is a ribonuclease, an enzyme that is capable of carrying out catalytic degradation of ribonucleic acids. <em>This means that if the RNA is treated with RNase before the plants are made to be exposed to it, they will not develop the lesions because the RNA would have been degraded by the enzyme.</em>
A protease is an enzyme that degrades the structure of proteins. <em>Treating a RNA with protease will thus have no effect on the structure of the RNA. Exposing the plants to the protease-treated RNA will make no difference. The plants will still come down with the lesions as if they have been exposed to the virus. </em>
