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maw [93]
3 years ago
15

Calculating Orbital Period The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. If HST has a tangential speed o

f 7,750 m/s, how long is HST’s orbital period? The radius of Earth is 6.38 × 106 m.
Physics
2 answers:
arsen [322]3 years ago
5 0
The answer is, 5630 seconds.
Vadim26 [7]3 years ago
5 0

Answer:

Orbital period, T = 93.89 minutes

Explanation:

It is given that,

The tangential speed of the Hubble Space Telescope, v = 7750 m/s

The radius of earth, r=6.38\times 10^6\ m

We need to find the orbital period of the Hubble Space Telescope that orbits 569 km above the Earth's surface i.e. h = 569 km = 569000 m

The orbital speed is given by,

v=\dfrac{2\pi R}{T}

T is the orbital period

R = r + h

R = 6949000 m

T=\dfrac{2\pi R}{v}

T=\dfrac{2\pi \times 6949000\ m}{7750\ m/s}

T = 5633.78 s

or

T = 93.89 minutes

So, the orbital period of the Hubble Space Telescope is 93.89 minutes. Hence, this is the required solution.

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maks197457 [2]

Question is missing:

"What is the gravitational force between the Sun and Jupiter?"

Answer:

4.16\cdot 10^{23} N

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have

m_1 = 1.99\cdot 10^{30} kg is the mass of the sun

m_2 = 1.90\cdot 10^{27} kg is the mass of Jupiter

r=7.79\cdot 10^8 km = 7.79\cdot 10^{11} m is their separation

Solving the equation, we find

F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(1.90\cdot 10^{27})}{(7.79\cdot 10^{11})^2}=4.16\cdot 10^{23} N

6 0
3 years ago
Two ice skaters push off against one another starting from a stationary position. The 54.1-kg skater acquires a speed of 0.375 m
asambeis [7]

Answer:

0.338125 m/s

Explanation:

Applying,

Law of conservation of momentum

m'v' = mv............ Equation 1

Where m' = mass of the first skater, v' = velocity of the first skater, m = mass of the second skater, v = velocity of the second skater.

make v the subject of the equation

v = m'v'/m........... Equation 2

From the question,

Given: m' = 54.1 kg, v' = 0.375 m/s, m = 60 kg

Substitute these values into equation

v = (54.1×0.375)/60

v = 20.2875/60

v = 0.338125 m/s

3 0
3 years ago
The term 'DENSITY' tells us…
pogonyaev

Answer:

The answer is A

Explanation:

Density basically shows the amount of mass per volume of something. You can easily find Density with the equation D=m/v

D= Density

m= mass

v= volume

3 0
3 years ago
A driver must always stop within 50 ft but not less than ____________ ft from the nearest rail when the signal is flashing and t
k0ka [10]

Answer:

20 ft

Explanation:

5 0
3 years ago
Read 2 more answers
jenny's model train is set up on a circular track. There are six telephone poles evenly spaced around the track. It takes the en
d1i1m1o1n [39]

Answer:

T = 60 s

Explanation:

There are 6 poles on the track which are equally spaced

so the angular separation between the poles is given as

\theta = \frac{2\pi}{6}

\theta = \frac{\pi}{3}

so the angular speed of the train is given as

\omega = \frac{\theta}{t}

\omega = \frac{\pi}{30} rad/s

now we have time period of the train given as

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{\frac{\pi}{30}}

T = 60 s

5 0
3 years ago
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